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Komok [63]
3 years ago
13

On the number line 0.2 would be located. Choose a answer to make a true statement.

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0
Um, there are no choices, so I'll just tell you were it'd be located

Since 0.2 isn't yet 1, but its value is more than 0, it would be located in the middle of 1 and 0. 
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Solve each equation by completing the square <br> 6) m² + 16m – 8 = 0
Natali5045456 [20]

Answer:

m = - 8 ± 6\sqrt{2}

Step-by-step explanation:

Given

m² + 16m - 8 = 0 ( add 8 to both sides )

m² + 16m = 8

To complete the square

add ( half the coefficient of the m- term )² to both sides

m² + 2(8)m + 64 = 8 + 64

(m + 8)² = 72 ( take the square root of both sides )

m + 8 = ± \sqrt{72} = ± \sqrt{36(2)} = ± 6\sqrt{2}

Subtract 8 from both sides

m = - 8 ± 6\sqrt{2}

3 0
3 years ago
Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
Can somebody help me with this math question?
kap26 [50]

Answer:Hk and IJ

Step-by-step explanation:

They are parallel to eachother, hope this helped!

<!> Brainliest is appreciated! <!>

6 0
3 years ago
Lest year Joe scored 80 point on his moth exam
mixer [17]

Answer:

20%

Step-by-step explanation:

decreased score= 80-64 = 16

x% of 80 = 16

x=20

5 0
3 years ago
Read 2 more answers
Petes dog weighed 30 pounds it then lost 16% of it's weight how much did pete lose
Vlad [161]

Answer:

The dog lost 4.8 pounds! Goodluck!


Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
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