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2 years ago

13

On the number line 0.2 would be located. Choose a answer to make a true statement.

1 answer:

Mariulka [41]2 years ago

6 0

Um, there are no choices, so I'll just tell you were it'd be located

Since 0.2 isn't yet 1, but its value is more than 0, it would be located in the middle of 1 and 0.

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Which statement describes whether a right triangle can be formed using one side length from each of these squares?

balu736 [363]

Answer:

Step-by-step explanation:

The area of the given squares are

Area = 64 in

Area = 225 in

Area = 289 in

The length of each side of a square is determined by finding the square root of its area. For the first square, the length of its side is √64 = 8inches. For the second square, the length of its side is √225 = 15inches. For the third square, the length of its side is √289 = 17inches.

For a right angle triangle to be formed, Pythagorean theorem must be obeyed. Sum of the square of the smaller sides must equal the square of the longer side. Therefore,

8² + 15² = 17²

289 = 289

Therefore, the correct statement is

Yes, a right triangle can be formed because the sum of the areas of the two smaller squares equals the area of the largest square

4 0

2 years ago

Help plz plz plz someone

Butoxors [25]

Answer:

C

Step-by-step explanation:

C = 2πr
2π = 2 × 3.14 = 6.28
6.28 × 8 = 50.24 feet

I hope this helps!

7 0

2 years ago

Read 2 more answers

P² +6r - 27<br> factoring quadratics

babunello [35]

Step-by-step explanation:

look at the picture shown

5 0

2 years ago

You get in an elevator and go down 8 floors. You exit on the 16th floor. Write and solve an equation to find what floor you got

disa [49]

So floor that you started is x
go down 8 means -8
end on 16

so
x-8=16
add 8
x=24

started on 24

3 0

3 years ago

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

so

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago