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Ainat [17]
3 years ago
15

Persephone is creating a flower garden in her back yard. If she needs 30 pounds

Mathematics
1 answer:
Likurg_2 [28]3 years ago
5 0
I thinks it’s B but I’m not sure sorry if not but B
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Determine all of the equations that have a solution of x=3
MakcuM [25]

a, b and e

a.

x + 5 = 8 ( subtract 5 from both sides )

x = 3

b

4x = 12 ( divide both sides by 4 )

x = 3

c

\frac{x}{9} = 3 ( multiply both sides by 9 )

x = 27

d

x - 5 = 10 ( add 5 to both sides )

x = 15

e

\frac{x}{1} = 3

note that \frac{x}{1} = x, hence

x = 3


8 0
3 years ago
Which numbers is 50 divisible by 2 , 5 , 10 , 15
meriva

Answer:

2, 5, 10

Step-by-step explanation:

50 divided by 2 = 25

50 divided by 5 = 10

50 divided by 10 = 5

50 divided by 15 = NOT POSSIBLE

8 0
4 years ago
Arnie jogs on 4 consecutive days.
SIZIF [17.4K]

Answer:

3 miles a day

Step-by-step explanation:

We can use the distance/time=speed formula:

12MI/4d = 3 miles a day

4 0
4 years ago
While exercising Ricardo walked 1/8 of a mile in 1/9 of an hour. At this rate, how far will he have travelled after an hour?
SSSSS [86.1K]

\bf \begin{array}{ccll} miles&hours\\ \cline{1-2}\\ \frac{1}{8}&\frac{1}{9}\\\\ x&1 \end{array}\implies \cfrac{~~\frac{1}{8}~~}{x}=\cfrac{~~\frac{1}{9}~~}{1}\implies \cfrac{~~\frac{1}{8}~~}{\frac{x}{1}}=\cfrac{1}{9}\implies \cfrac{1}{8x}=\cfrac{1}{9} \\\\\\ 9=8x\implies \cfrac{9}{8}=x\implies 1\frac{1}{8}=x

6 0
4 years ago
Find the unknown side of the triangle and explain!!!
klasskru [66]

Since this is a right triangle, we can use Pythagorean theorem. Pythagorean theorem is a^2 + b^2 = c^2

a = one leg of the triangle

b = the second leg of the triangle

c = the hypotenuse of the triangle

in this problem,

a = 8 in

b = 6 in

c = ?

We need to plug our numbers into the pythagorean theorem and solve for c

8^2 + 6^2 = c^2.

Square each term on the left side.

64 + 36 = c^2

Add the terms together on the left side.

100 = c^2.

Take the square root of each side

10 = c

The missing side is 10 inches

7 0
4 years ago
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