The first one is the last answer because you subtract 18 and when you divide you change the inequality symbol
the second one is the last answer for the same reason
the 3rd one is x<-1.25
the 4th one is x<8/15
Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 0.54% of the calls receive a busy signal, hence p = 0.0054.
- A sample of 1300 callers is taken, hence n = 1300.
The probability that at least 5 received a busy signal is given by:

In which:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).
Then:






Then:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

0.8295 = 82.95% probability that at least 5 received a busy signal.
More can be learned about the binomial distribution at brainly.com/question/24863377
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Answer:
80 ft x 40 ft
Step-by-step explanation:
Let 'L' be the length of the longer side and 'W' be the length of the shorter side (or the width).
The equations that compose the linear system are:

Solving the system:

The garden is a rectangle with dimensions 80 ft x 40 ft.
Answer:
1a- Alternate Exterior Angles
1b- Alternate Interior Angles
1c-Alternate Exterior Angles
1d-Alternate Interior Angles
1e-Alternate Exterior Angles
1f-Alternate Interior Angles
2a-None
2b-None
2c-Alternate Exterior Angles
2d-None
2e-Alternate Interior Angles
2f-None
2g-None
2h-None
2i-None
2j-None
I’m assuming a. Or 26 since it’s the only number within the range