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3 years ago

15

Persephone is creating a flower garden in her back yard. If she needs 30 pounds

1 answer:

Likurg_2 [28]3 years ago

5 0

I thinks it’s B but I’m not sure sorry if not but B

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If y = - 4/5x - 2, what is the value of x when y = - 9

MrRa [10]

Y = -4/5 x - 2
-9 = -4/5 x - 2
-4/5 x = -9 + 2 = -7
-4x = 5(-7) = -35
x = -35/-4 = 35/4

3 0

3 years ago

The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func

katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle ( $\frac{1}{3},\frac{1}4$ ).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A( $\frac{1}{3},\frac{1}4$ )

Let O be the origin i.e. (0,0)

Point B will be ( $\frac{1}{3},0$ )

Now, let us consider the right angled triangle $\triangle OBA$ :

Sides:

$Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}$

Using Pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}$

$sin \angle AOB = \dfrac{Perpendicular}{Hypotenuse}$

$\Rightarrow sin \angle AOB = \dfrac{\frac{1}{4}}{\frac{5}{12}}\\\Rightarrow sin \angle AOB = \dfrac{3}{5}$

$cos\angle AOB = \dfrac{Base}{Hypotenuse}$

$\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}$

$tan\angle AOB = \dfrac{Perpendicular}{Base}$

$\Rightarrow tan\angle AOB = \dfrac{3}{4}$

$cosec \angle AOB = \dfrac{Hypotenuse}{Perpendicular}$

$\Rightarrow cosec\angle AOB = \dfrac{5}{3}$

$sec\angle AOB = \dfrac{Hypotenuse}{Base}$

$\Rightarrow sec\angle AOB = \dfrac{5}{4}$

$cot\angle AOB = \dfrac{Base}{Perpendicular}$

$\Rightarrow cot\angle AOB = \dfrac{4}{3}$

3 0

2 years ago

Can a triangle be drawn with the following angle measures? Why or why not?<br> 50°, 70°, 70°

Viefleur [7K]

no, the 3 angles of a triangle need to equal 180 degrees

70 +70 +50 = 190 degrees so it cant be a triangle.

4 0

3 years ago

Read 2 more answers

Find the length of AB. Leave

vovikov84 [41]

Answer:

<em>AB = 3π</em>

Step-by-step explanation:

<em>See attachment for correct format of question.</em>

Given

From the attachment, we have that

θ = 20°

Radius, r = 27

Required

Find length of AB

AB is an arc and it's length can be calculated using arc length formula.

$Length = \frac{\theta}{360} * 2\pi r$

<em>Substitute 20 for θ and 27 for r</em>

$Length = \frac{20}{360} * 2\pi *27$

$Length = \frac{20 * 2\pi * 27}{360}$

$Length = \frac{1080 \pi}{360}$

$Length = 3\pi$

Hence, the length of arc AB is terms of π is 3π

3 0

3 years ago

Let f(x) = -5x - 4 and g(x) = 6x - 7. Find f(x) + g(x)

DIA [1.3K]

Answer:

x - 11

Step-by-step explanation:

Let f(x) = -5x - 4 and g(x) = 6x - 7.

f(x) + g(x)

I like to line them up vertically

-5x - 4

6x - 7

--------------

x-11

8 0

3 years ago