Question

The vertex of the equation of a parabola is y=4 (x-2)^2-1. what is the standard form of the equation

Answer 1

y=4 (x-2)^2-1
y = 4(x^2 - 4x + 4) -1
y = 4x^2 - 16x + 16 - 1
y = 4x^2 - 16x + 15

answer
standard form
y = 4x^2 - 16x + 15