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USPshnik [31]
3 years ago
12

A captain and a co-captain are randomly selected from the 12 members of a fencing team. Determine the probability that Lauren is

chosen as the captain, and Isabel is chosen as the co-captain
Mathematics
2 answers:
Lilit [14]3 years ago
4 0

I'm not 100% sure of this  I think its as follows:-

Prob(Lauren then Isabel picked)  = 1/12 * 1/11 = 1/132 



olga2289 [7]3 years ago
3 0
A captain<span> and </span>co-captain<span> for a </span>fencing team<span> are </span>chosen<span> from a hat with the ...</span>Determine<span> the </span>probability<span> that </span>Lauren<span> and </span>Isabel<span> are </span>chosen<span> a</span>
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I NEED HELP ASAP!!!!
Tcecarenko [31]

Answer:

The closest to 36 would be 6in

The 8 box would be 64in²

The 10 box would be 100in²

Step-by-step explanation:

We have to square or square root the numbers

√36 is 6

8² is 64

10² is 100

5 0
3 years ago
Someone please help ASAP will give brainliest
Roman55 [17]

Answer:

  sqrt(ac)

±----------  = b

    3c

Step-by-step explanation:

a= 9b^2 c

Divide each side by 9c

a/9c = 9b^2c / 9c

a/9c= b^2

Take the sqrt of each side

±sqrt(a/9c) = sqt(b^2)

Remember that sqrt (xy) = sqrt(x) sqrt(y)

±sqrt(a/c) * 1/ sqrt(9) = b

±sqrt(a)     1

--------- * ------ = b

sqrt(c)     3

Multiply  by sqrt(c)/ sqrt(c)

±sqrt(a)     sqrt(c)

--------- * -----------   = b

sqrt(c)     3sqrt(c)

±sqrt(ac)

----------  = b

3c

6 0
3 years ago
The endpoints of DE and D(-3, y) and x, 6). The midpoint of DE is M(4,2). What is the length of DE.
Natasha_Volkova [10]

If the endpoints of DE where D(-3, y) and E(x, 6) with the midpoint M(4, 2), the length of DE is 16.12 units

The formula for calculating the midpoint is expressed as;

M(x,y)=(\frac{x_1+x_1}{2}, \frac{y_1+y_2}{2})

For the x-coordinate points:

X = -3+x/2

4 * 2 = -3 + x

8 = -3 + x

x = 8 + 3

x = 11

Get the value of y;

2 = y+6/2

y+6 = 2 * 2

y + 6 = 4

y = 4 - 6

y = -2

Hence the coordinates of D and E are D(-3, -2) and E(11, 6)

D=\sqrt{(6-(-2))^2+(11-(-3))^2}\\D=\sqrt{8^2+14^2}\\D=\sqrt{64 + 196}\\D=   \sqrt{260}\\D= 16.12units

Hence the length of DE is 16.12 units

Learn more here; brainly.com/question/22624745

3 0
2 years ago
A​ quality-control inspector examined 100 light bulbs and found 7 defective. At this​ rate, how many defective bulbs would there
anastassius [24]

Answer: 175 defective bulbs.

Step-by-step explanation:

1. Keeping on mind that the inspector examined 100 light bulbs and found 7 defective, you can calculate the number of defective bulbs that there would be in a lot of 2500 ​bulbs as following:

- Let's call the number of defective bulbs that there would be in a lot of 2500 ​bulbs x.

- Then, you have:

\frac{100}{7}=\frac{2500}{x}

- Solve for x:

 x=\frac{2500*7}{100}

x=175

2. Then, there would be 175 defective bulbs  in a lot of 2500 ​bulbs.


4 0
3 years ago
What is the value of x/(4x +7) [5(x-4)]
Anon25 [30]

Answer:

(4x+7) [5(x-4)]

(4x+7)(5x-20)

20x^2-80x+35x-140

20x^2-45x-140

6 0
3 years ago
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