Answer:
The closest to 36 would be 6in
The 8 box would be 64in²
The 10 box would be 100in²
Step-by-step explanation:
We have to square or square root the numbers
√36 is 6
8² is 64
10² is 100
Answer:
sqrt(ac)
±---------- = b
3c
Step-by-step explanation:
a= 9b^2 c
Divide each side by 9c
a/9c = 9b^2c / 9c
a/9c= b^2
Take the sqrt of each side
±sqrt(a/9c) = sqt(b^2)
Remember that sqrt (xy) = sqrt(x) sqrt(y)
±sqrt(a/c) * 1/ sqrt(9) = b
±sqrt(a) 1
--------- * ------ = b
sqrt(c) 3
Multiply by sqrt(c)/ sqrt(c)
±sqrt(a) sqrt(c)
--------- * ----------- = b
sqrt(c) 3sqrt(c)
±sqrt(ac)
---------- = b
3c
If the endpoints of DE where D(-3, y) and E(x, 6) with the midpoint M(4, 2), the length of DE is 16.12 units
The formula for calculating the midpoint is expressed as;

For the x-coordinate points:
X = -3+x/2
4 * 2 = -3 + x
8 = -3 + x
x = 8 + 3
x = 11
Get the value of y;
2 = y+6/2
y+6 = 2 * 2
y + 6 = 4
y = 4 - 6
y = -2
Hence the coordinates of D and E are D(-3, -2) and E(11, 6)

Hence the length of DE is 16.12 units
Learn more here; brainly.com/question/22624745
Answer: 175 defective bulbs.
Step-by-step explanation:
1. Keeping on mind that the inspector examined 100 light bulbs and found 7 defective, you can calculate the number of defective bulbs that there would be in a lot of 2500 bulbs as following:
- Let's call the number of defective bulbs that there would be in a lot of 2500 bulbs
.
- Then, you have:

- Solve for x:


2. Then, there would be 175 defective bulbs in a lot of 2500 bulbs.