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Bond [772]
3 years ago
5

A 15-inch candle burns down in 10 hours. at what rate does the candle burn in inches per hour

Mathematics
2 answers:
Monica [59]3 years ago
8 0

Answer:

5 inches per hour

Step-by-step explanation:

valentina_108 [34]3 years ago
3 0

Answer:

1.5 inches per hour

Step-by-step explanation:

You might be interested in
Find the next 3 terms in the geometric sequence -36, 6, -1, 1/6, ...
timama [110]

we are given

geometric sequence -36, 6, -1, 1/6, ...

first term is -36

a_1=-36

now, we can find common ratio

r=\frac{6}{-36}

r=-\frac{1}{6}

now, we can find nth term

a_n=a_1(r)^{n-1}

now, we can plug values

and we get

a_n=36(-\frac{1}{6})^{n-1}

now, we can find 5th term , 6th term, 7th term

fifth term:

a_5=36(-\frac{1}{6})^{4}

a_5=\frac{1}{36}

sixth term:

a_6=36(-\frac{1}{6})^{5}

a_6=-\frac{1}{216}

seventh term:

a_7=36(-\frac{1}{6})^{6}

a_7=\frac{1}{1296}

so, next terms are

a_5=\frac{1}{36} , a_6=-\frac{1}{216}

, a_7=\frac{1}{1296}.............Answer

6 0
3 years ago
An industrial printing machine printed 1764 pages in 6 minutes. How much would it have printed in 4 minutes?
vladimir2022 [97]

Answer:

1176

Step-by-step explanation:

i hope this helps out

8 0
4 years ago
-6(2x + 4) = 12 what is the answer <br>​
katrin2010 [14]
The answer to your question is -3 !!
3 0
3 years ago
Read 2 more answers
Please help!! this is the question right here
Sidana [21]
John is correct because between the time and distance, you divide by 9 to get the distance or multiply by 9 to get the time.
6 0
3 years ago
What is the rectangular equivalence to the parametric equations?
denpristay [2]

Answer:

For x(θ) = 3cosθ + 2

y² = [9x²/(x - 2)²] - x²

For x(θ) = 3cosθ + 2

x² = [4y²/(y - 1)²] - y²

Step-by-step explanation:

Given the following equivalence:

x² + y² = r²

r = √(x² + y²)

x = rcosθ

cosθ = x/r

y = rsinθ

sinθ = y/r

Applying these to the given equations,

x(θ) = 3cosθ + 2

x = 3(x/r) + 2

xr = 3x + 2r

(x - 2)r = 3x

r = 3x/(x - 2)

Square both sides

r² = 9x²/(x - 2)²

(x - 2)²r² = 9x²

(x - 2)²(x² + y²) = 9x²

(x² + y²) = 9x²/(x - 2)²

y² = [9x²/(x - 2)²] - x²

y(θ) = 2sinθ - 1

y = 2y/r - 1

yr = 2y - r

(y - 1)r = 2y

r = 2y/(y - 1)

Square both sides

r² = 4y²/(y - 1)²

x² + y² = 4y²/(y - 1)²

x² = [4y²/(y - 1)²] - y²

8 0
3 years ago
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