When you hit a ball it collides with the bat. When you catch a ball it collides with your hand.
The age of a man whose normal blood pressure measures 123 mm of hg
9 years
<h3>What is Quadratic equation ?</h3>
A quadratic equation as an equation of degree 2, meaning that the highest exponent of this function is 2. The standard form of a quadratic equation is y = a
+ bx + c, where a, b, and c are numbers and a cannot be 0
P(A) = 0.006 
- 0.02a + 120
123 = 0.006- 0.02a + 120
0=0.006 - 0.02a - 3
you can use the quadratic equation formula to solve for the man's age.
A = (-b ± (
) ) / (2a)
A = (0.02 ± 
/ (2*0.006)
A = (0.02 ± 
) / 0.012
A = 9 , -5.67
Age of the man will be 9 years
To learn more about quadratic equation here
brainly.com/question/17177510?referrer=searchResults
#SPJ4
complete question:
A child bounces a 60 g superball on the sidewalk. The velocity change of the superball is from 22 m/s downward to 15 m/s upward. If the contact time with the sidewalk is 1/800 s, what is the magnitude of the average force exerted on the superball by the sidewalk
Answer:
F = 1776 N
Explanation:
mass of ball = 60 g = 0.06 kg
velocity of downward direction = 22 m/s = v1
velocity of upward direction = 15 m/s = v2
Δt = 1/800 = 0.00125 s
Linear momentum of a particle with mass and velocity is the product of the mass and it velocity.
p = mv
When a particle move freely and interact with another system within a period of time and again move freely like in this scenario it has a definite change in momentum. This change is defined as Impulse .
I = pf − pi = ∆p
F = ∆p/∆t = I/∆t
let the upward velocity be the positive
Δp = mv2 - m(-v1)
Δp = mv2 - m(-v1)
Δp = m (v2 + v1)
Δp = 0.06( 15 + 22)
Δp = 0.06(37)
Δp = 2.22 kg m/s
∆t = 0.00125
F = ∆p/∆t
F = 2.22/0.00125
F = 1776 N
Volume = mass / density = 45.6/10.5 = .... L
Answer:
0.0006091222 m
Explanation:
q = Charge = 42 pC
V = Voltage = 620 V
= Permittivity of free space = 
Electric potential is given by (at r = R)
The radius of the drop is 0.0006091222 m
