Assuming that all energy of the small ball is transferred
to the bigger ball upon impact, then we can say that:
Potential Energy of the small ball = Kinetic Energy of
the bigger ball
Potential Energy = mass * gravity * height
Since the small ball start at 45 cm, then the height
covered during the swinging movement is only:
height = 50 cm – 45 cm = 5 cm = 0.05 m
Calculating for Potential Energy, PE:
PE = 2 kg * 9.8 m / s^2 * 0.05 m = 0.98 J
Therefore, maximum kinetic energy of the bigger ball is:
<span>Max KE = PE = 0.98 J</span>
Answer:
Explanation:
From the question, we were made to understand that the collision between the two billiard balls was an elastic collision. Hence, an elastic collision is one in which the kinetic energy is conserved. Meaning the kinetic energy before the collision is still retained after the collision.
Kinetic energy before collision = kinetic energy after collision
1/2mv^2 = 1/2mv^2
There was no gain nor loss in energy
<span>Answer:
I'm pretty sure the SA / V ratio would get smaller. Assume that the cell is more or less spherical. SA = 4(pi)r^2, while V = (3/4)(pi)r^3. The ratio = (4(pi)r^2)/((3/4)(pi)r^3), which can be simplified to 3/r. Thus, the larger r gets, the smaller the ratio becomes.</span>
P2o3 is <span>diphosphorus trioxide.
Add water and you get phosphoric acid</span>
