What is the average velocity of a dragster that starts from rest at the starting line and finishes a race at 2600 m/s in 12 seco
1 answer:
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Answer:
The block would have slid <u>12.6 m</u> if its initial velocity were increased by a factor of 2.8.
Explanation:
Given:
Mass of the block (m) = 3.6 kg
Initial velocity (u) = 1.7 m/s
Final velocity (v) = 0 m/s
Displacement (S) = 1.6 m
First we will find the acceleration of the block.
Using the equation of motion, we have:
Now, plug in the given values and solve for 'a'. This gives,
The acceleration is negative as it is resisting the motion.
Now, the initial velocity is increased by a factor of 2.8. So,
New initial velocity = 2.8 × 1.7 = 4.76 m/s
Again using the same equation of motion and expressing the result in terms of 'S'. This gives,
Now, plug in the given values and solve for 'S'. This gives,
Therefore, the block would have slid 12.6 m if its initial velocity were increased by a factor of 2.8
Answer:
0.426 volts
Explanation:
It is given that,
The radius of a circular loop, r = 11.2 cm = 0.112 m
An elastic conducting material is stretched into a circular loop.
It is placed with its plane perpendicular to a uniform 0.880 T magnetic field.
The radius of the loop starts to shrink at an instantaneous rate of 68.8 cm/s, dr/dt = 0.688 m/s
We need to find the emf induced in the loop at that instant.
So, the magnitude of induced emf is 0.426 volts.