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3 years ago

What would happen to the planets in the solar system if the sun’s gravitational force were to suddenly disappear?

Physics

2 answers:

Mazyrski [523]3 years ago

8 0

I believe the answer would be B.

Hope this helps!

elena-s [515]3 years ago

3 0

Answer:

B. They will fly away in straight lines.

Explanation:

They wouldn't have the gravity to keep them in place so they would fly away.

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A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 60.0 m/s , and it leav

nata0808 [166]

Answer:

F = -307.4 N

Explanation:

It is given that,

Mass of the baseball, m = 0.145 kg

Initial speed of the baseball, u = 60 m/s

Final speed of the baseball, $v=65\ cos(30)=56.29\ m/s$

Time of contact, $t=1.75\ ms=1.75\times 10^{-3}\ s$

(a) It is assumed to find the horizontal component of average force. It is given by :

$F=m\dfrac{v-u}{t}$

$F=0.145\dfrac{56.29-60}{1.75\times 10^{-3}}$

F = -307.4 N

So, the horizontal component of average force is 307.4 N. Hence, this is the required solution.

8 0

3 years ago

How can i calculate distances between objects by using the concepts of echo location

dangina [55]

Send wave from your location to the object and wait until echo is back.
Measure the time taken.

If you know the speed of wave (say sound wave), than just multiply by half time taken wave to return

5 0

3 years ago

Assume you are given an int variable named nElements and a two-dimensional array that has been created and assigned to a2d. Writ

Alex777 [14]

Answer:

Explained

Explanation:

public int dimension(int [][]a2d,int nElements)

{

int count = 0;

for(int i = 0;i < a2d.length ; i++)

{

count = count + a2d[i].length;

}

return count;

}

3 0

3 years ago

In this experiment, you will use a track, a toy car, and some washers to explore Newton’s first two laws of motion. You will mak

polet [3.4K]

How can we experimentally verify newton's laws?

7 0

3 years ago

Read 2 more answers

Belly-flop Bernie dives from atop a tall flagpole into a swimming pool below. His potential energy at the top is 7000 J (relativ

elena55 [62]

Answer:

KE₂ = 6000 J

Explanation:

Given that

Potential energy at top U₁= 7000 J

Potential energy at bottom U₂= 1000 J

The kinetic energy at top ,KE₁= 0 J

Lets take kinetic energy at bottom level = KE₂

Now from energy conservation

U₁+ KE₁= U₂+ KE₂

Now by putting the values

U₁+ KE₁= U₂+ KE₂

7000+ 0 = 1000+ KE₂

KE₂ = 7000 - 1000 J

KE₂ = 6000 J

Therefore the kinetic energy at bottom is 6000 J.

5 0

3 years ago