Given:
rod of circular cross section is subjected to uniaxial tension.
Length, L=1500 mm
radius, r = 10 mm
E=2*10^5 N/mm^2
Force, F=20 kN = 20,000 N
[note: newton (unit) in abbreviation is written in upper case, as in N ]
From given above, area of cross section = π r^2 = 100 π =314 mm^2
(i) Stress,
σ
=force/area
= 20000 N / 314 mm^2
= 6366.2 N/mm^2
= 6370 N/mm^2 (to 3 significant figures)
(ii) Strain
ε
= ratio of extension / original length
= σ / E
= 6366.2 /(2*10^5)
= 0.03183
= 0.0318 (to three significant figures)
(iii) elongation
= ε * L
= 0.03183*1500 mm
= 47.746 mm
= 47.7 mm (to three significant figures)
Answer:
milligrams
explanation:
kilograms are too big
<em>Hope this helps :)</em>
Yes, but the velocity of the bullet would have to be much higher. Because momentum is defined as p=mv, for a bullet, which has a much, much smaller mass than a car or a truck, to have the same value for p,
Answer:
Explanation:
The total charge in the disks

must be conserved before and after bringing them together.
Lets equate the sum of the initial charge with the sum of the final for the disk:


So, the initial charges must sum +17 μC.
Now, as there are no charges over +17 μC, this means that both charges must be positive.
As the only positive charges are
and
, this disk must be the ones we are looking for. And, as we can see, they sum 17 μC:
