Question

A lead ball is added to a graduated cylinder containing 41.7 ml of water, causing the level of the water to increase to 96.0 mL. What is the volume in milliliters of the lead ball, Vieras? Viead =

Answer 1

Answer:

$Vlead ball=54.3 mL$

Explanation:

The graduated cylinder contains $41.7mL$ of water

mL is a volume unit.

Water volume = 41.7 mL

The lead ball caused an increase of volume from 41.7 mL to 96.0 mL

The new volume is the lead ball volume plus the original water volume :

Final volume = Vlead ball+ Water original volume

$96.0mL=Vleadball +41.7mL$

$Vlead ball=96.0mL-41.7mL$

$Vleadball=54.3mL$

This is actually true if we suppose that the lead ball is fully sunken in the water.

We always must consider that the volume difference is the volume that the sunken object is occupying in the water.