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Juli2301 [7.4K]
3 years ago
13

The valency of sodium metal

Chemistry
1 answer:
Ronch [10]3 years ago
3 0

Answer:

The atomic number of sodium is 11 (Z=11). The electronic configuration of sodium can be written as 2, 8, 1. Therefore, valence electron in sodium is 1 and it needs to lose 1 electron from the outermost orbit to attain octet. Hence, the valency of sodium is 1.

Explanation:

Hope this helps! Mark me as the brainliest

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Which of the following is a common property noble gases
ss7ja [257]

Answer:

Noble gases are non reactive

Explanation:

This is because they are thermodynamically very stable

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Why is chemistry important? i need 5 paragraph please
Travka [436]

Answer:

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6 0
3 years ago
Read 2 more answers
You perform recrystallization of 1 g of impure acetanilide from water. The solubility of pure acetanilide in hot water is 55g/L.
likoan [24]

Answer:

38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.

Explanation:

Mass of acetanilide to be dissolved in hot water = 2.1 g

Mass of hot water to be used = m

Solubility of acetanilide = 55 g/L

This means that 55 grams of acetanilide dissolves in 1 L of hot water.

Then 1 grams of acetanilide will dissolve in :

\frac{1}{55}\times 2.1 L=0.0382 L

0.0382 L = 0.0382 × 1000 mL =38.2 mL

1 L = 1000 mL

38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.

8 0
3 years ago
What is the result of multiplying 2.5 times 10 to the power 10 by 3.5×10 to the power of -7
AURORKA [14]

Answer:

8.75 × 10³

Explanation:

Multiply the coefficients and the exponential terms separately; then multiply them together

2.5 × 3.5 = 8.75.

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10¹⁰ × 10⁻⁷ = 10⁽¹⁰⁻⁷⁾ = 10³

The product is 8.75 × 10³.

A scientific calculator does the operation automatically. The buttons may have different labels on your calculator, but the key sequence is usually something like

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6 0
3 years ago
How much energy (in J) is lost when a sample of iron with a mass of 26.4 g cools from 74.0 ∘C to 26.0 ∘C?
Greeley [361]

Answer:

Q=-526.6J

Explanation:

Hello,

In this case, for the computation of the energy loss when the cooling process is carried out, we use the shown below equation:

Q=mCp\Delta T

Whereas we need the mass, specific heat and change in temperature of iron within the process. Thus, the only value we need is the specific heat that is 0.444 J/(g°C), therefore, we compute the heat loss:

Q=26.4g*0.444\frac{J}{g\°C}*(26.0\°C-74.0\°C)\\ \\Q=-526.6J

Negative sign points out the loss due to the cooling.

Regards.

8 0
4 years ago
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