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pogonyaev
3 years ago
14

Glycolysis is the process by which energy is harvested from glucose by living things. Several of the reactions of glycolysis are

thermodynamically unfavorable (nonspontaneous), but proceed when they are coupled with other reactions. Which of these reactions is(are) unfavorable? Select all that apply.
(A) P1 + Glucose → Glucose-6-phosphate + H2O ΔG⁰= 3.30 kcal/mol
(B) P1 + Fructose-6-phosphate → Fructose-1.6-biphosphate + H2O ΔG⁰=3.9 kcal/mol
(C) ATP + H2O → ADP + P1 ΔG⁰=-7.30 kcal/mol
Chemistry
1 answer:
sertanlavr [38]3 years ago
3 0

Answer:

Reaction A and B are unfavorable.

Explanation:

Gibbs free energy is an energy which that can be use to convert into useful work.

ΔG°=ΔH°-TΔS°

ΔG°= Gibbs free energy

ΔH° =  enthalpy of reaction

T = temperature of eh reaction

ΔS° = Entropy change

  • If the Gibbs  free energy of the reaction is positive than the reaction will be non spontaneous and the chemical reaction will be not feasible.
  • If the Gibbs  free energy of the reaction is negative than the reaction will be spontaneous and the chemical reaction will be feasible .

According to given information in the question:

Reaction A and B are non spontaneous as their Gibbs free energy value is positive.hence both are unfavorable.

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Explanation:

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6 0
3 years ago
Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life
skelet666 [1.2K]

The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually, radioactive elements have an unstable atomic nucleus.  

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

\tt 3\times 12.4=37.2~hours

3 0
3 years ago
a sample of ammonia liberates 5.66 kj of heat as it solidifies at its melting point . what is the mass of the sample?
Reil [10]
The correct answer for the question that is being presented above is this one: "<span>16.728 g."</span>

Given that 
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This means that 5.66 kJ of heat is released when 1 mole of NH3 solidifies 

When 5.57 kJ of heat is released
amount of NH3 solidifies = 5.57/5.66 = 0.984 moles 

<span>molar mass of NH3 = 17 g/mole </span>
<span>1 mole of NH3 = 17 g </span>
So, 0.984 moles of NH3 = 17 X 0.984 = 16.728 g
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Finding the concentration for each sample's absorbance on the standard curve is the first step in calculating the sample concentration based on the standard curve. The next step is to multiply the concentration by the dilution factor for each sample.

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vekshin1

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