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pogonyaev
3 years ago
13

Write the equation of a circle with a center at (-12, -11) and a radius of 7.​

Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0

let h=-12, k=-11 then

(x-h)^2 + (y-k)^2= r^2

(x+12)^2 + (y+11)^2 = 7^2

x^2 + 24x + 144 + y^2 + 22y + 121 = 49

x^2 + y^2 + 24x + 22y + 144+121-49= 0

x^2 + y^2 + 24x + 22y + 216 = 0 is the required eq

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Answer:

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Step-by-step explanation:

(n+4)/10 = (n-8)/2

We can solve using cross products

(n+4) * 2 = 10 * ( n-8)

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2n+8-2n = 10n-80-2n

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Add 80 to each side

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