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pogonyaev
3 years ago
13

Write the equation of a circle with a center at (-12, -11) and a radius of 7.​

Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0

let h=-12, k=-11 then

(x-h)^2 + (y-k)^2= r^2

(x+12)^2 + (y+11)^2 = 7^2

x^2 + 24x + 144 + y^2 + 22y + 121 = 49

x^2 + y^2 + 24x + 22y + 144+121-49= 0

x^2 + y^2 + 24x + 22y + 216 = 0 is the required eq

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FIANCE 50 HELP ASAP
Assoli18 [71]

Calculate the risk measure (beta) compared to the returns of asset and market premium.

1.4 = 4 + 9((rm^-4)

1.4 = 9rm ^-32

33.4 = 9rm

Rm = 3.71

The answer is 3.71

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2 years ago
Three single-digit numbers multiply to make 504 Write the missing numbers
boyakko [2]
We will guess and check to solve this problem

504/9= 56
504/8= 63
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we can continue the pattern. However, we know that 50 is the product of 8 and 7, so we can use that number

9*8*7=504
3 0
3 years ago
Write the equation of the line that passes through the points (-7, 7) and (-6, -5).
defon

Answer:

y = -12x - 77

Step-by-step explanation:

The standard form of the equation is expressed as y = mx+b

m is the slope

Given the coordinate (-7, 7) and (-6, -5).

m = -5-7/-6+7

m = -12/1

m = -12

Get the intercept b

Substitute m= -12 and (-7 7) into y = mx+b

7 = -12(-7) + b

7 = 84 + b

b = 7 - 84

b = -77

Get the required equation

y = mx+b

y = -12x +(-77)

y = -12x - 77

This gives the required equation

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2 years ago
Introduction to the Quadratic Formula
vredina [299]

Answer:

Any questions for us

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3 years ago
Which choice is the equation of the line that passes through the point (5, 19) and has a slope of
Liono4ka [1.6K]

Answer:

The equation is;

y = 12x-41

Step-by-step explanation:

Mathematically;

slope intercept form is;

y = mx + b

where m is slope and b is intercept

Since we already have the slope , the equation is;

y = 12x + b

To get b which is the y intercept, we simply substitute the value of the points given

Thus;

19 = 5(12) + b

19 = 60+ b

b = 19-60

b = -41

So the equation is;

y = 12x - 41

3 0
2 years ago
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