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erma4kov [3.2K]
3 years ago
14

which choice represent's the simplified exponential expression? (15^-6)9 A.15 B.15^-54 C.15^3 D.15^-15

Mathematics
1 answer:
frez [133]3 years ago
7 0

Answer:

B

Step-by-step explanation:

15^(-6*9) = 15^-54

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A colony of cats were introduced into a reserve. The number of cats present at timet(measured in years since the colony was intr
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ANSWER:

a) 12 cats

b) 232

c) 246

d) 14

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Given the expression for number of cats C present at time t:

C\text{ = }\frac{12.31}{0.05+0.56^t^{}}

a) To find the number of cats initially on the reserve, let t = 0

Therefore, substitute 0 for t in the equation

\begin{gathered} C\text{ = }\frac{12.31}{0.05+0.56^0} \\ \text{   = }\frac{12.31}{0.05\text{ + 1}} \\ \text{   = }\frac{12.31}{1.05} \\ =\text{ }11.72 \end{gathered}

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b) C(10):

\begin{gathered} C(10)\text{ = }\frac{12.31}{0.05+0.56^{10}}\text{ = 232.12} \\  \end{gathered}

C(10) = 232

Here, C(10) means that C is a function of 10. This means at time = 10 years

C)Using function notation to express the number of cats present after 17 years, we have:

C(17)\text{ = }\frac{12.31}{0.05+0.56^{17}}

C(17)\text{ = }\frac{12.31}{0.05+0.56^{17}}\text{ = }245.94

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C(17) = 246 cats

d) In this case, first find the number of cats present in the 10th year and subtract from the number of cats present in the 17th year.

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Therefore, the increase in cat population to be expected from the 10th year to the 17th year is:

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