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Daniel [21]
3 years ago
6

What is 5 radians converted to degrees? If necessary, round your answer to the nearest degree.

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0

Answer:

286 degrees

Step-by-step explanation:

Your formula would be 5 x 180/π

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At what interest rate must you invest $4500 to have $7,000 after 6 years, if the interest is compounded quarterly?
labwork [276]

Answer:

The amount is $8358.7 and the interest is $3858.7.

Step-by-step explanation:

Explanation

STEP 1: To find amount we use formula:

A=P(1+rn)n⋅t

A = total amount

P = principal or amount of money deposited,

r = annual interest rate

n = number of times compounded per year

t = time in years

In this example we have

P=$4500 , r=7% , n=2 and t=9 years

After plugging the given information we have

AAAA=4500(1+0.072)2⋅9=4500⋅1.03518=4500⋅1.857489=8358.7

STEP 2: To find interest we use formula A=P+I, since A=8358.7 and P = 4500 we have:

A8358.7II=P+I=4500+I=8358.7−4500=3858.7

4 0
3 years ago
What is the median of 1.6 , 2.3 , 1.4 , 2.5 , 1.7
lisov135 [29]

First, reorder the numbers from least to greatest

1.4, 1.6, 1.7, 2.5, 2.5

The median is the middle number

1.7 is your answer

hope this helps

6 0
3 years ago
Here's a linear equation. rewrite it in slope-intercept form -2-3y+15=0​
irakobra [83]
-3y-2+15=0 would be the answer
3 0
3 years ago
Read 2 more answers
Combine like terms, then simplify if need be.<br><br> 4cx + cx – cx – cx + cx
Crank

Answer:

4cx

hope this helps

have a good day :)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Use the quadratic formula to solve 9x2 + 6x – 17 = 0. A. B. x = –1, –5 C. D.
Taya2010 [7]

Answer:

x_{1} = -\frac{1}{3} +\sqrt{2} ; x_{2} = -\frac{1}{3}-\sqrt{2}

Step-by-step explanation:


9x² + 6x – 17 = 0

Apply the quadratic formula

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

a = 9; b = 6; y = -17

x = \frac{-6\pm\sqrt{6^2 - 4\times 9 \times(-17)}}{2\times 9}

x = \frac{-6\pm\sqrt{36+36\times17}}{18}

x = \frac{-6\pm\sqrt{36(1+17)}}{18}

x = \frac{-6\pm 6 \sqrt{18}}{18}

x = \frac{-1\pm \sqrt{9\times2}}{3}

x = \frac{-1\pm 3\sqrt{2}}{3}

x_{1} = -\frac{1}{3} +\sqrt{2} ; x_{2} = -\frac{1}{3}-\sqrt{2}

The graph below shows the roots at x₁ =1.081 and x₂ = -1.748.

6 0
3 years ago
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