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soldier1979 [14.2K]

3 years ago

10

What is the maximum number of times two planes can intersect? What is the minimum number of times they can intersect?

1 answer:

nordsb [41]3 years ago

8 0

The minimum number of times two planes can intersect is zero, because if the planes are parallel to each other, they will never intersect. we can take the example of floor and roof, both are parallel to each other and no intersection. If the two planes are in same plane the maximum number of times they can intersect is infinite for example if we consider a line we can intersect at infinite points.

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the triplex theater has 3 different movies tonight: bucket of fun, bozo the great, and pickle man. each movie has an early and l

serious [3.7K]

Bucket of fun. bozo the great. pickleman
/ \ / \ / \
day night day night day. night

theres three movie choices

5 0

3 years ago

Solve the equation<br> 12 + 4m = 24<br> A)m=9<br> B)m=8<br> C)m=3<br> D)m=-6

pantera1 [17]

12 +4m = 24

4m = 12

m = 12/4

m = 3 so choice C. is right sure

8 0

3 years ago

At a pie cook-off, the judges ate 512 of Mary’s pie and 916 of Jerome’s pie.

IRISSAK [1]

Answer:

No

Step-by-step explanation:

I think you meant to put 5/12 ad 9/16 but in any case, even if it were 51/2 and 91/6 or anything else, the answer would be no

6 0

2 years ago

one-third of the people from country A claim that they are from country B, and the rest admit they are from country A. One-fourt

In-s [12.5K]

Answer: 3 : 2

Step-by-step explanation:

Let A represents the total population of country A and B represents the total population of country B.

According to the question,

$\text{The population of country A that admit they are from B} = \frac{1}{3}\text{ of }A$

⇒ $\text{ The population of A that admit they are from country A }= A - \frac{1}{3} \text{ of } A$

$= \frac{3-1}{3} A$

$= \frac{2}{3} A$

$\text{The population of country B that admit they are from A} = \frac{1}{4}\text{ of }B$

⇒ $\text{ The total population that claims that they are from A }= \frac{2}{3} A +\frac{1}{4} B$

But, Again according to the question,

The total population that claims that they are from A = one half of the total population of A and B.

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}(A+B)$

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B$

⇒ $\frac{2}{3} A + \frac{1}{4} B= \frac{1}{2}A+\frac{1}{2}B$

⇒ $\frac{2}{3} A - \frac{1}{2}A= \frac{1}{2}B-\frac{1}{4} B$

⇒ $\frac{4}{6} A - \frac{3}{6}A= \frac{2}{4}B-\frac{1}{4} B$

⇒ $\frac{1}{6} A = \frac{1}{4} B$

⇒ $A =\frac{6}{4}B$

⇒ $\frac{A}{B} =\frac{3}{2}$

8 0

3 years ago

A 13-A ladder leans against the side of a house. The bottom of the ladder is 8 ft from the side of the house. How high is the to

Anit [1.1K]

Answer:

10.2 ft

Step-by-step explanation:

$a^{2} +b^{2} = c^{2} \\8^{2} +b^{2} =13^{2} \\$

64 + $b^{2}$ = 169

$b^{2} = 105\\$

b= $\sqrt{105}$

b= 10.2469

5 0

2 years ago