<span>20, 19, 13, 23, 16, 15, 17, 17, 15, 15, 22, 19
</span>To find the Median, place the numbers in value order<span> and find the </span>middle<span>.
</span>
13, 15, 15, 15, 16, 17, 17, 19, 19, 20, 22, 23
There are 12 numbers and so we don't have just one middle number, we have a pair of middle numbers:
13, 15, 15, 15, 16,
(17, 17), 19, 19, 20, 22, 23
<span>To find the value halfway between them, add them together and divide by 2:
</span>
17 + 17 = 34
34 ÷ 2 = 17
So the median is A) 17.
Answer:
Step-by-step explanation:
Given that Rafaela is a physical education teacher and has 25 girls and 35 boys in her class.
She wants to divide the class into teams of the same size, where each team has the same number of girls and the same number of boys. If Rafaela creates the greatest number of teams possible, how many boys will be on each team?
Here we find Highest common factor for 25 and 35 and it is 5
So 5 boys will be on each team (with 7 girls)
2) length I = 7m, x12 m and height = 3mx85 cm.
The longest tape would be the highest common factor of 12 and 85
Since it is 1, only 1 cm long tape can be used.
Answer:
She needs to buy more chocolate chips≥
Step-by-step explanation:
The outlet pipe will take 18 hours to empty the tank.
St<u>ep-by-step explanation:</u>
Number of hours taken by inlet pipe to fill the tank=6
work done by the inlet pipe in 1 hour=1/6
Number of hours taken by the inlet pipe to fill the tank with the outlet pipe open=9
work done by the inlet pipe in 1 hour with outlet pipe open=1/9
we have to determine the time taken by the outlet pipe to empty the tank
The inlet and outlet pipe does the opposite work.
The outlet pipe takes 18 hours to empty the tank.
Answer:
Step-by-step explanation:
We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:
Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:
5^2 = 3^2 + x^2
x = 4
The radius is 4 + 1 cm = 5 cm
So the area of the circle is A = pi*r^2
A = 3.14 * (5)^2
A = 25pi cm^2
To solve for the area of the shaded region:
Ashaded = Acircle - Atriangles
we need to solve for the area of the triangles:
A = 1/2 *b*h
A = 1/2 *6 * 5
A = 15 cm^2
Atriangles = 2 * 15
Atriangles = 30 cm^2
Ashaded = 25pi - 30
