Hello! $800 was the past amount for rent and now it's $900. 900 - 800 is 100. that's a $100 difference. In order to find the percent increase in the rent, we can write and sovle a proportion. It would be set up as change/original = x/100, where change is difference between two numbers and original is the previous price. It would be set up like this:
100/800 = x/100
Let's crossmultiply the values. 100 * 100 is 10,000. 800 * x is 800x. That makes 10,000 = 800x. Now, divide each side by 800 to isolate the x. 800x/800 cancels out. 10,000/800 is 12.5 or 12.5%. Let's check this by multiplying by 112.5%. 800 * 112.5% (1.125) is 900. That's what we're looking for! There. x = 12.5%. The percent increase is 12.5%.
Answer is x=13.
basically you put them together and make them =180
Answer:C got more by 57 to 43 which is 14
Step-by-step explanation:
45.136 is the answer I got
You haven't listed the possible solutions, so in the immediate present I can help only by suggesting that you try solving this system and checking your own answers thru subst. into the given equations.
Please be sure to use "^" to indicate exponentiation, as shown below:
<span>4x2 + 9y2 = 72 should be 4x^2 + 9y^2 = 72 (this is the eq'n of an ellipse)
x - y2 = -1 should be x - y^2 = -1 (this is the equation of a parabola)
We must eliminate either x or y. I will solve the 2nd equation for y^2 and subst. the result into the first eq'n.:
y^2 = x+1. Subst. this into the first equation,
</span>4x^2 + 9y^2 = 72 becomes 4x^2 + 9(x+1) = 72.
Expanding, 4x^2 + 9x + 9 = 72, or 4x^2 + 9x - 63 = 0
We must solve this quadratic equation to obtain the x-coordinates of possible solutions of the original system of equations.
-9 plus or minus 33
After some work, we get x = ------------------------------
8
So x = 24/8 = 3, or x = -42/8 = -5 1/4 or -21/4
Check out x=3. We already have the relationship y^2 = x+1. If x = 3, then y^2 = 3+1 = 4, and y is plus or minus 2.
Two possible solutions of the original set of equations are thus (3,2) and (3,-2). You MUST check both solutions thru substitution to determine whether they satisfy the original equations or not.
