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telo118 [61]
2 years ago
14

Jully bought 3 slices of cheese pizza and 4 slices of pepperoni pizza for $18.00. Christian bought 3 slices of cheese pizza and

2 slices of pepperoni for $12.00. What is the cost for one slice of cheese pizza?
Mathematics
1 answer:
andrew11 [14]2 years ago
8 0

Answer:

$2.00

Step-by-step explanation:

You can form an equation with these statements, x being the price of cheese pizza and y being the price of pepperoni. Making the equation,

3x+4y=18

3x+2y=12

Solving the equation,

3x+4y=18

6x+4y=24

-3x=-6

x=2

y=3

Solving another way,

2y=6

y=3

x=2

Therefore, the answer is $2.00

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9. Khalid drove 66 miles on 3 gallons of gasoline. Which is the number of miles he could drive on 12 gallons of gasoline?
IrinaK [193]

Answer:

264 miles

Step-by-step explanation:

Find the unit rate (mpg):

 66 miles

----------------- = 22 mpg

 3 gallons

On 12 gallons he could drive (22 mpg)(12 gallons) = 264 miles

8 0
3 years ago
Is it possible for a triangle to have sides with the given lengths: 20 m, 22 m, and 24 m? A. Yes; the sum of each pair is greate
snow_lady [41]
The correct answer is A) yes, the sum of each pair is greater than the third.

The triangle inequality theorem states that the sum of any two sides of a triangle is longer than the third side. This is true for these numbers, so this does form a triangle.
3 0
3 years ago
Read 2 more answers
Kevin is 3 years older than Daniel. Two years ago, Kevin was 4 times as old as Daniel.
goldfiish [28.3K]

Answer:

B is the correct answer

Kevin is K

Daniel is D

Now: K

K = D + 3

3 years ago:

K - 2 = 4(d - 2)

<h2>YOURE WELCOME, PLEASE MARK AS BRAINLIEST AND FOLLOW ME ❤️❤️</h2>

6 0
3 years ago
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An environmental group conducted a study to determine whether crows in a certain region were ingesting food containing unhealthy
nydimaria [60]

Part A

Given info:

  • xbar = sample mean = 4.90 ppm
  • s = sample standard deviation = 1.12 ppm
  • n = 23 = sample size

Because n > 30 is not true, and we don't know the population standard deviation (sigma), this means we must use a T distribution.

The degrees of freedom here are n-1 = 23-1 = 22.

At 90% confidence and the degrees of freedom mentioned, the t critical value is roughly t = 1.717

Use a T distribution table or calculator to determine this. If you don't have a calculator for the task, then you can search out "inverse T calculator" and there are tons of free options to pick from.

The margin of error E is

E = t*s/sqrt(n)

E = 1.717*1.12/sqrt(23)

E = 0.400982

This is approximate and accurate to 6 decimal places.

The confidence interval is going to be xbar plus or minus that E value

L = lower bound = xbar - E = 4.90 - 0.400982 = 4.499018 = 4.50

U = upper bound = xbar + E = 4.90 + 0.400982 = 5.300982 = 5.30

The confidence interval in the format of (L, U) is (4.50, 5.30)

You could also express it as the format L < mu < U and it would be 4.50 < mu < 5.30; however, I'll stick to the first method.

<h3>Answer:  (4.50, 5.30)</h3>

=====================================================

Part B

Since we know sigma = 2.6 is the population standard deviation, we can use a Z distribution now.

At 90% confidence, the z critical value is roughly 1.645; use a table or calculator to determine this.

n = \left(\frac{z*\sigma}{E}\right)^2\\\\n \approx \left(\frac{1.645*2.6}{0.03}\right)^2\\\\n \approx 20325.254444 \\\\

Round this up to the nearest integer to get 20326. For min sample size problems, <u>always</u> round up.

<h3>Answer: 20326</h3>
6 0
2 years ago
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