All categories

4 years ago

He sees a red ring and a faint white ring that looks like a crown, which part of the sun is he seeing

Chemistry

1 answer:

Ira Lisetskai [31]4 years ago

4 0

He is seeing the corona it's the crown like layer that you see when there is a solar eclipse ☀️

You might be interested in

For carbon monoxide poisoning, the treatment is administration of oxygen at high pressure. This increases the amount of oxyhemog

Mama L [17]

Adding oxygen will cause the equation of
CO-Hemogoblin + O2= Hemogoblin = Oxyhemogoblin

to the right. This is because the increase in pressure leads to more on the left side, and as such a balance needs to be maintained so the equation shifts to the right.

3 0

3 years ago

Read 2 more answers

Water is moving across a membrane from solution a into solution

leva [86]

The answer is solution a must have a lower solute concentration than solution b.

That is when water is moving across a membrane from solution a into solution b, then solution a must have a lower solute concentration than solution b.

When solution a have a lower solute concentration than solution b, then water moves across a membrane from solution a into solution b.

7 0

4 years ago

2. A chemical analysis of a sample provides the following elemental data:

Vadim26 [7]

Answer:

C3 H6 O2

Explanation:

first divide their mass by their respective molar mass, we get:

30.4 moles of C

61.2 moles of H

20.25 moles of O

now divide everyone by the smallest one of them then we get

C= 1.5

H= 3

O= 1

since our answer of C is not near to any whole number so we will multiply all of them by 2

so,

C3 H6 O2 is our answer

3 0

2 years ago

How is oxygen different than neon explain your answer

lora16 [44]

Oxygen and neon are both elements. Oxygen has 8 electrons and 8 protons. Neon has 10 electrons and 10 protons. Oxygen is also a non-metal element and Neon is a noble gas.

5 0

3 years ago

The Michaelis constant for pancreatic lipase is 5 mM. At 60 C, lipase is subject to deactivation with a half-life of 8 min. Fat

Dmitriy789 [7]

Explanation:

According to the given data, we will calculate the following.

Half life of lipase $t_{1/2}$ = 8 min x 60 s/min

= 480 s

Rate constant for first order reaction is as follows.

$k_{d} = \frac{0.6932}{480}$

= $1.44 \times 10^{-3}s^{-1}
$

Initial fat concentration $S_{o}$ = 45 $mol/m^{3}$

= 45 mmol/L

Rate of hydrolysis $V_m_{o}$ = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration (S) = $S_{o} (1 - X)$

= 45 (1 - 0.80)

= 9 $mol/m^{3}$

or, = 9 mmol/L

It is given that $K_{m}$ = 5mmol/L

Therefore, time taken will be calculated as follows.

t = $-\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]$

Now, putting the given values into the above formula as follows.

t = $-\frac{1}{K_{d}}ln[1 - \frac{K_{d}}{V}{K_{M} ln (\frac{S_{o}}{S}) + (S_{o} - S)]$

= $-\frac{1}{1.44 \times 10^{-3}s^{-1}}ln[1 - \frac{1.44 \times 10^{-3}s^{-1}}{0.07 mmol/L/s
}{K_{M} ln (\frac{45 mmol/L
}{9 mmol/L
}) + (45 mmol/L - 9 mmol/L
)]$

= $1642.83 s \times \frac{1 min}{60 sec}$

= 27.38 min

Therefore, we can conclude that time taken by the enzyme to hydrolyse 80% of the fat present is 27.38 min.

6 0

3 years ago