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sergij07 [2.7K]
3 years ago
7

What is the reason for the trend in lonization Energy? Select all that apply.

Chemistry
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

Explanation:

A, D,E and B i think is the correct answers  

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How many liters of 0.1107 M KCI contains 15.00 g of KCI (FW= 74.6 g/mol)
Mashcka [7]
Number of moles:

n = sample mass / molar mass

n = 15.00 / 74.6

n = 0.2010 moles of KCl

Therefore:

Molarity = moles / Volume

0.1107 = 0.2010 / V

V = 0.2010 / 0.1107

V = 1.815 L 


8 0
3 years ago
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What is the law of conservation of energy? a. Energy is created and destroyed. b. Energy is not created but is destroyed. c. Ene
Lady bird [3.3K]

Answer:

Energy is neither created nor destroyed.

Explanation:

The law of conservation of energy states that energy can neither be created nor be destroyed. The total energy of an isolated system remains conserved. It never gets 0. It changes from one form of energy to other but never vanishes.

Hence, the correct option is (d) "Energy is neither created nor destroyed"

8 0
2 years ago
The breakdown of dopamine is catalyzed by the enzyme monoamine oxidase (MAO). What is the final concentration of product if the
kotegsom [21]

Answer:

final concentration: Ca = 0.014 M

Explanation:

Velocity of reaction:

  • ra = K(Ca)∧α = δCa/δt

∴ α: order of reaction, assuming α = 1

∴ K = 0.249 s-1.......rate constant

∴ Cao = 0.050 M......initial concentration

∴ t = 5 s.......reaction time

⇒ δCa/δt = K*Ca

⇒ ∫δCa/Ca = K*∫δt

⇒ Ln(Cao/Ca) = K*t = (0.249s-1)(5 s) = 1.245

⇒ Cao/Ca = 3.473

⇒ Ca = 0.050/3.473

⇒ Ca = 0.014 M

3 0
2 years ago
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stoichiometric amounts of nitrogen gas and hydrogen gas react in a calorimeter to produce 5.00 g of ammonia gas. the calorimeter
mario62 [17]
First, we determine the energy released by the reaction using the heat capacity and change in temperature as such:

Q = cΔT
Q = 32.16 * 0.42
Q = 13.51 kJ

Next, we determine the moles of ammonia formed as the heat of formation is expressed in "per mole".

Moles = mass / molecular weight
Moles = 5/17
Moles = 0.294

Heat of formation = 13.51 / 0.294

The heat of formation of ammonia is 45.95 kJ/mol
6 0
3 years ago
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A 20.0 g piece of a metal is heated and place into a calorimeter containing 250.0 g of water initially at 25.0 oC. The final tem
BartSMP [9]

Answer:

Q_{metal} = -6799\,J

Explanation:

By the First Law of Thermodynamics, the piece of metal and water reaches thermal equilibrium when water receives heat from the piece of metal. Then:

Q_{metal} = - Q_{w}

Q_{metal} = m_{w} \cdot c_{p,w}\cdot (T_{1}-T_{2})

Q_{metal} = (250\,g)\cdot \left(4.184\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (25\,^{\textdegree}C - 31.5\,^{\textdegree}C)

Q_{metal} = -6799\,J

6 0
3 years ago
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