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Nikitich [7]
2 years ago
10

Drag each label to the correct location on the equation. Each label may be used more than once.

Chemistry
1 answer:
elena-14-01-66 [18.8K]2 years ago
8 0
HCl is an acid, C5H5N is a base, Cl is an acid, and HC5H5N is an acid.

Hope this helps! If so, brainliest would be appreciated!
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Volume can be measured in:
Anna11 [10]
Volume can be measured in cubic centimetres (which is the small 3 next to the unit and is higher)
4 0
4 years ago
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Given: CaC2 + N2 → CaCN2 + C In this chemical reaction, how many grams of N2 must be consumed to produce 265 grams of CaCN2? Exp
weeeeeb [17]

Answer : The grams of N_2 consumed is, 89.6 grams.

Solution : Given,

Mass of CaCN_2 = 265 g

Molar mass of CaCN_2 = 80 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate the moles of CaCN_2.

\text{Moles of }CaCN_2=\frac{\text{Mass of }CaCN_2}{\text{Molar mass of }CaCN_2}=\frac{265g}{80g/mole}=3.2moles

The given balanced reaction is,

CaC_2+N_2\rightarrow CaCN_2+C

from the reaction, we conclude that

As, 1 mole of CaCN_2 produces from 1 mole of N_2

So, 3.2 moles of CaCN_2 produces from 3.2 moles of N_2

Now we have to calculate the mass of N_2

\text{Mass of }N_2=\text{Moles of }N_2\times \text{Molar mass of }N_2

\text{Mass of }N_2=(3.2moles)\times (28g/mole)=89.6g

Therefore, the grams of N_2 consumed is, 89.6 grams.

5 0
3 years ago
Read 2 more answers
How many moles are in 715.11 grams of Ca(C2H302)2?
nikdorinn [45]

Answer:

4.52 mol

Explanation:

We do grams/Molar Mass to find the number of moles. The grams are given but the molar mass, you have to add all masses of the elements up by refering to a periodic table, and you should get that the compound has a mass of 158.168. Do 715.11 dived by that and you get the answer above.

3 0
3 years ago
1). How can the position of a particle be determined?
Kamila [148]

1).C-by analyzing its interactions with another particle

2).C-18

3).C-energy sub-level


8 0
3 years ago
A 0.180 m solution of a weak acid (ha) has a ph of 2.91. calculate the acid ionization constant (ka) for the acid.
N76 [4]
Answer is: <span>the acid ionization constant (Ka) for the acid is </span>8.46·10⁻⁶.
Chemical reaction: HA(aq) ⇄ H⁺(aq) + A⁻(aq).
pH = 2,91.
[H⁺] = 10∧<span>-2,91 = 0,00123 M.
</span>[H⁺] = [A⁻] = 0,00123 M.
[HA] = 0,18 M - 0,00123 M.
[HA] = 0,1787 M.
Ka = [H⁺] · [A⁻] / [HA].
Ka = (0,00123 M)² / 0,1787 M.
Ka = 8,46·10⁻⁶ M.
3 0
3 years ago
Read 2 more answers
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