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MA_775_DIABLO [31]
3 years ago
8

What are the three phases of matter

Chemistry
2 answers:
Hitman42 [59]3 years ago
7 0
The three include Solids, Liquids, and Gases
Alex17521 [72]3 years ago
3 0

Answer:

gas liquid and solid

Explanation:

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How many moles contain 5.34 x 10^26 atoms of iron?
SCORPION-xisa [38]

Answer: 1.31 × 10^47 sorry if its not the answer

Explanation:

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2 years ago
10.0 mL of 3.0 M sulfuric acid has been added to 50.0 mL of water.
Cloud [144]

Answer:

the new concentration is 0.60M

Explanation:

The computation of the new concentration is shown below;

We know that

M1V1=M2V2

(3.0M) (10.0 mL) = M2 (50.0mL)

30 = M2 (50.0mL)

So, M2 = 0.60 M

Hence, the new concentration is 0.60M

The same is considered and relevant

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3 years ago
charcoal removes fine particulates, as well as lead, mercury, copper, and chlorine from water through a separation process calle
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Absorption distillation floatation filtration
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3 years ago
Speed-48km time-5hour​
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7 0
3 years ago
Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el
LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>
8 0
3 years ago
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