Answer:
b) 49.48% C, 5.19% H, 28.85% N, and 16.48% O
Explanation:
we find the mass for each element in one mole by multiplying the number of atoms in one molecule with the atomic mass
mC=8Ac=8*12=96g
mH=10AH=10*1=10g
mN=4AN=4*14=56g
mO=2AO=2*16=32g
by adding the masses together we find the molar mass of the molecule
M=mC+nH+mN+mO=96+10+56+32=194g/mole
we apply the rule of threes to find the percentage of each element
194g..96gC..10gH...56gN....32gO
100g....a...........b...........c.............d
a=(100*96)/194=49.48%C
b=(100*10)/194=5.19%H
c=(100*56)/194=28.85%N
d=(100*32)/194=16.48%O
First of all, we convert the amount of item given in moles into grams. Each mol of steam is 18 grams of steam. Such that the heat released during the evolution of per gram of steam is,
H = (2.01 J/goC)(160 - 100) + 2260 J/g + (4.179 J/gC)(100 - 0) + (333.5 J/g) + (2.09 J/gC)(45oC)
H = 3226.05 J/g
Then, we multiply this value by 18 g to get the final answer which is equal to 58068.9 Joules.
Answer:
Circular motion
Explanation:
Consider a car race, where you need to finish one lap in a circuit. Her the start line and the finish line are the same. So , where you start, is where you will be reaching after the race is done. So, the displacement here is <em>Zero</em> , since displacement is the distance from initial point to final point. But, as one can see, the distance travelled is not zero.
Say the race track is a circle of radius r meters. So the lap distance would be the circumference of the circle, which is 2πr m. So the distance travelled is 2πr m and the displacement is zero.
Hope this satisfies you :)
Answer : The molecular weight of this compound is 891.10 g/mol
Explanation : Given,
Mass of compound = 12.70 g
Mass of ethanol = 216.5 g
Formula used :
where,
= change in freezing point
= temperature of pure ethanol = 
= temperature of solution = 
= freezing point constant of ethanol = 
i = van't hoff factor = 1 (for non-electrolyte)
m = molality
Now put all the given values in this formula, we get
Therefore, the molecular weight of this compound is 891.10 g/mol
