For A:
Your longest carbon chain is 5 so it's overall a pentane
you have 2 branchings on Carbon 2 and 4; and the branchings are methyl groups
so the name would be 2,3-dimethylpentane
Give me a little on B: It's giving me some trouble
Plants do not need Oxygen because they take in <span>Carbon Dioxide and make
</span><span>Oxygen they don't need </span> <span>Oxygen</span>
Answer:
pH = 2.21
Explanation:
Hello there!
In this case, according to the reaction between NaF and HCl as the latter is added to the buffer:

It is possible for us to see how more HF is formed as HCl is added and therefore, the capacity of this HF/NaF-buffer is diminished as it turns acid. Therefore, it turns out feasible for us to calculate the consumed moles of NaF and the produced moles of HF due to the change in moles induced by HCl:

Next, we calculate the resulting concentrations to further apply the Henderson-Hasselbach equation:
![[HF]=\frac{0.450mol}{1.0L} =0.450M](https://tex.z-dn.net/?f=%5BHF%5D%3D%5Cfrac%7B0.450mol%7D%7B1.0L%7D%20%3D0.450M)
![[NaF]=\frac{0.050mol}{1.0L} =0.050M](https://tex.z-dn.net/?f=%5BNaF%5D%3D%5Cfrac%7B0.050mol%7D%7B1.0L%7D%20%3D0.050M)
Now, calculated the pKa of HF:

We can proceed to the HH equation:
![pH=pKa+log(\frac{[NaF]}{[HF]} )\\\\pH=3.17+log(\frac{0.05M}{0.45M} )\\\\pH=2.21](https://tex.z-dn.net/?f=pH%3DpKa%2Blog%28%5Cfrac%7B%5BNaF%5D%7D%7B%5BHF%5D%7D%20%29%5C%5C%5C%5CpH%3D3.17%2Blog%28%5Cfrac%7B0.05M%7D%7B0.45M%7D%20%29%5C%5C%5C%5CpH%3D2.21)
Best regards!
Answer:
90.35 × 10²³ atoms
Solution:
1 molecules of H20 contains 3 atoms,.
And we know that one mole of any molecule contains 6.023 × 10²³ atoms from Avogadro's number,
hence 5 moles of H20 will contain = 5× 6.023 × 10²³ × 3 atoms = 90.35 × 10²³ atoms!
<em><u>Thanks for joining brainly community!</u></em>
Answer:
Both a Geologic and Topographic map. So C. is the Answer.
Explanation: