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S_A_V [24]
4 years ago
14

What is the predominant intermolecular force between ibr molecules in liquid ibr?

Chemistry
2 answers:
jasenka [17]4 years ago
8 0

Answer is: dispersion forces.

The London dispersion force is the weakest intermolecular force.

Dispersion force is also called an induced dipole-induced dipole attraction.

The London dispersion force (intermolecular force) is a temporary attractive force between molecules.

The dipole beetween iodine and bromine is weak.

Naily [24]4 years ago
5 0
<span>1) dispersion forces. These are electron-rich compounds, and the electrons are relatively far away from the nucleus and each other. The electrons on one molecule see the positive core (Effective Nuclear Charge) of the next molecule, and draw the first molecule closer. This pretty much describes dispersion forces. </span>
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Suppose a car sitting on a hydraulic lift exerts a downward force of 1,750 N on a piston with an area of 0.6m2. How much pressur
soldier1979 [14.2K]
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6 0
3 years ago
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What pressure is requred to contain 0.023 moles of nitrogen gas in a 4.2 L container at a
zubka84 [21]

Answer:

0.13 atm

Explanation:

Using the Ideal Gas Law; PV=nRT, we can rearrange to solve for pressure.

P=nRT/V

P is pressure, n is number of moles (0.023), R is a constant (0.08206 L*atm/mol*K), T is temperature in Kelvin (293.15K) and V is volume, 4.2 L.

So, plugging in;

P=(0.023mol)(0.08206L*atm/mol*K)(293.15K)/(4.2 L)

P=0.1317 atm

P=0.13 atm; multiply by 760 to get to Torr or mmHg.

5 0
2 years ago
Water (2150 gg ) is heated until it just begins to boil. If the water absorbs 5.91×105 JJ of heat in the process, what was the i
Serjik [45]

Answer:

Initial temperature of water was 34,3°C

Explanation:

The heat absorbed in the process (Q) can be written as:

Q = mcΔT

Where the heat is 5,91x10⁵J, m is mass of water (2150g), c is specific heat of water (4,184J/g°C). And ΔT is change in temperature (100°C - x). Replacing:

5,91x10⁵J = 2150g×4,184J/g°C×(100°C - x)

5,91x10⁵J = 899560J - 8995,6J/°Cx

-3,0856x10⁵J = - 8995,6J/°Cx

34,3°C = x

Thus, <em>initial temperature of water was 34,3°C</em>

I hope it helps!

3 0
3 years ago
20 PTS!!!! easy question plz answer
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6 0
4 years ago
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3 years ago
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