Answer:
the pressure of the gas in torr is 2280 torr
Explanation:
The pressure of a gas in torr can be calculated by converting its pressure in kPa to atmospheres and then converting the atmospheric pressure to torr.
One atmosphere is equal to 101.325 kPa. Therefore, the pressure of the gas in atmospheres is 305 kPa / 101.325 kPa/atm = 3.00 atm.
One torr is equal to 1/760 of an atmosphere. Therefore, the pressure of the gas in torr is 3.00 atm * 760 torr/atm = 2280 torr.
Therefore, the pressure of the gas in torr is 2280 torr
C) gas particles move rapidly but they collide with each other as well as on the wall of the container
Answer:
U are a fool
Explanation:
Because you didn't even asked a question
Answer:
It takes 6h to the radioactive source decrease its activity from 200 to 25
Explanation:
The equation that describes the readioactive decay is:
Ln [A] = -kt + Ln [A]₀
<em>Where [A] could be taken as activity of the source after time t, [A]₀ is initial activity and k is decay constant.</em>
<em />
Decay constant could be written as:
k = ln2 / Half-life
k = ln 2 / 2h
k = 0.3466h⁻¹
Replacing in decay equation:
Ln [25] = -0.3466h⁻¹t + Ln [200]
-2.0794 = -0.3466h⁻¹t
6h = t
It takes 6h to the radioactive source decrease its activity from 200 to 25
