Answer:
978 J
General Formulas and Concepts:
<u>Thermodynamics</u>
Specific Heat Formula: q = mcΔT
- q is heat (in J)
- m is mass (in g)
- c is specific heat (in J/g °C)
- ΔT is change in temperature (in °C)
Explanation:
<u>Step 1: Define</u>
[Given] <em>c</em> = 4.18 J/g K
[Given] <em>m</em> = 6.00 g
[Given] ΔT = 75.0 °C - 36.0 °C = 39.0 °C
[Solve] <em>q</em>
<u>Step 2: Find </u><em><u>q</u></em>
- Substitute in variables [Specific Heat Formula]: q = (6.00 g)(4.18 J/g K)(39.0 °C)
- Multiply [Cancel out units]: q = 978.12 J
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
978.12 J ≈ 978 J
Answer:
high melting and boiling points
Explanation:
Answer:
qualitive
Explanation:
Qualitative observation deals with data that can be observed with our senses: sight, smell, touch, taste, and hearing.
Step 1; write the molecular equation, that is
NaBr(aq) +AgNO3 (aq)---> AgBr(s) +NaNO3 the equation is balanced
ionic equation is therefore
Na+(Aq) +Br- (aq) + Ag+(aq) + No3-(aq) --->AgBr(s) +Na+(aq) + No3-(aq)
net equation
Ag+(aq) +Br-(aq) --->AgBr(s)
Hydrophilic;
Polar compounds
water
ions
glucose
Hydrophobic;
Triglycerides
cholesterol
Lipids
Oil
Carbohydrates
<h3>What are hydrophilic substances?</h3>
The term hydrophilic substances is used to describe the substances that could dissolve in water. They are those substances that are water soluble. Somehow, the substances must be polar because in chemistry like dissolves like.
The hydrophobic substances are those substances that do not dissolve in water. They are nonpolar and interact with other nonpolar substances.
The classification of the substances took place below;
Hydrophilic;
Polar compounds
water
ions
glucose
Hydrophobic;
Triglycerides
cholesterol
Lipids
Oil
Carbohydrates
Learn more about hydrophilic substances:brainly.com/question/4692308
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