Answer:
74 units squared
Step-by-step explanation:
we know that the area of a square or rectangle is A = L × w
so we should just separate the object into it's individual rectangles/squares, solve for their areas, then add them together.
so I'll start with the middle square its length is 8 and width is 8 too.
A = 8 × 8
A = 64
now we'll move on to the other small ones to the side.
the one on the right side it's length is 2 and width is 2.
A = 2 × 2
A = 4
and then the last one on the left, Length is 3, width is 2.
A = 2 × 3
A = 6
now we'll add up all of the areas to get the total area.
Total = 64 + 4 + 6
Total = 74 units squared
Answer:
x = 2i, x = -2i and x = 4 are the roots of given polynomial.
Step-by-step explanation:
We are given the following expression in the question:

One of the zeroes of the above polynomial is 2i, that is :

Thus, we can write

Now, we check if -2i is a root of the given polynomial:

Thus, we can write

Therefore,

Dividing the given polynomial:

Thus,

X = 4 is a root of the given polynomial.

Thus, 2i, -2i and 4 are the roots of given polynomial.
Answer: nickels = 14, dimes = 42, quarters = 18
<u>Step-by-step explanation:</u>
Let n represent nickels <em>which has a value of $0.05 </em>
Let d represent dimes <em>which has a value of $0.10</em>
Let q represent quarters <em>which has a value of $0.25</em>
It is given that:
n = n
d = 3n
q = n + 4
and their total value is $9.40 ⇒ n + d + q = $9.40
Use substitution to find the quantity of nickels:
.05(n) + .10(3n) + .25(n + 4) = 9.40
5n + 10(3n) + 25(n+4) = 940 <em>multiplied by 100 </em>
5n + 30n + 25n + 100 = 940 <em>distributed</em>
60n + 100 = 940 <em>added like terms</em>
60n = 840 <em>subtracted 100</em>
n = 14 <em>divided by 60</em>
n = 14
d = 3n
= 3(14)
= 42
q = n + 4
= (14) + 4
= 18
Uncle peter-relative
january-month
jesse owens-athlete
william shakespeare-author
sunday-day
chrysler-automobile
Answer: a) Mean = 5, Median = 5
b) Mean = 15, Median = 5
c) Due to presence of outlier i.e. 99.
Step-by-step explanation:
Since we have given that
1,2,3,4,5,6,7,8,9
Here, n = 9 which is odd
So, Mean would be

Median = 
If 9 is replaced by 99,
1,2,3,4,5,6,7,8,99
So, mean would be

Median would be same as before i.e. 5
The mean is neither central nor typical for the data due to outlier i.e. 99
Hence, a) Mean = 5, Median = 5
b) Mean = 15, Median = 5
c) Due to presence of outlier i.e. 99.