X=5 and y =2.
Here's how you do it.
Multiply the first equation by -3, and the second one by 1.
add the equations to eliminate x.
then solve for y by dividing both sides by -5, which gives us 2.
to solve for x subsitute 2 in for y.
Answer:
One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.
Step-by-step explanation:
First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
12^2 - 6^2 * 3^4 + 5^3
(144) - (36) * (81) + (125)
144 - (36 * 81) + 125
144 - 2916 + 125
-2,772 + 125
-2,647
I assumed you meant red instead of wet.
To calculate this, multiply 28% (which is the same as .28) times 300.
300 x .28 = 84
