Answer:
30°
Step-by-step explanation:
∠A + ∠B + ∠C = 180
∠B = ∠A + 20
∠C = 2 * ∠B
<A + (∠A + 20) + (2 * ∠B) = 180
<A + (∠A + 20) + (2 * (∠A + 20)) = 180
<A + (∠A + 20) + 2∠A + 40 = 180
4∠A + 60 = 180
4∠A = 120
∠A = 30
Answer: The answer is A. -21
Its simplified and i just multiplied 3 by -7 :)
Answer:
% Po lost = 100[1 - e^(-0.005t)] %; 73.0 g
Step-by-step explanation:
p(t) = 100e^(-0.005t)
Initial amount: p(0) = 100
Amount remaining: p(t) = 100e^(-0.005t)
Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]
% of Po lost = amount lost/initial amount × 100 %
= [1 - e^(-0.005t)] × 100 % = 100[1 - e^(-0.005t)] %
p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g
The mass of polonium remaining after 63 days is 73 g.
Answer:
4
Step-by-step explanation:
duh
No 11.473 is greater then 11.447