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Len [333]
3 years ago
11

The table shows the amount of a radioactive sample that remains after a certain number of days. use the data in the table to des

cribe the relationship between the number of milligrams remaining and days. the sample originally weighed __ mg.
The relationship is best modeled by ________ function that _________.

Mathematics
1 answer:
My name is Ann [436]3 years ago
3 0

Answer:

1. 10 mg

2. an exponential

3. decreases only

Step-by-step explanation:

its correct

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2 years ago
Find the coordinates of the point three tenths<br><br> of the way from A(-4, -8) to B(11, 7)
Leviafan [203]

let's first off take a peek at those values.

let's say the point with those coordinates is point C, so C is 3/10 of the way from A to B.

meaning, we take the segment AB and cut it in 10 equal pieces, AC takes 3 pieces, and CB takes 7 pieces, namely AC and CB are at a 3:7 ratio.


\bf ~~~~~~~~~~~~\textit{internal division of a line segment}&#10;\\\\\\&#10;A(-4,-8)\qquad B(11,7)\qquad&#10;\qquad \stackrel{\textit{ratio from A to B}}{3:7}&#10;\\\\\\&#10;\cfrac{A\underline{C}}{\underline{C} B} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(-4,-8)=3(11,7)\\\\[-0.35em]&#10;~\dotfill\\\\&#10;C=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em]&#10;~\dotfill


\bf C=\left(\cfrac{(7\cdot -4)+(3\cdot 11)}{3+7}\quad ,\quad \cfrac{(7\cdot -8)+(3\cdot 7)}{3+7}\right)&#10;\\\\\\&#10;C=\left( \cfrac{-28+33}{10}~~,~~\cfrac{-56+21}{10} \right)\implies C=\left( \cfrac{5}{10}~~,~~\cfrac{-35}{10} \right)&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;~\hfill C=\left( \frac{1}{2}~,~-\frac{7}{2} \right)~\hfill

4 0
3 years ago
What is the solution of the system of equations? Y=x-4 and y=-3x
nata0808 [166]

Answer:

<u>(-7,-3)</u>

Step-by-step explanation:

step one) solve one equation for x.

y=-3x

-3x/-3=y/-3

x=(-y/3)

step two) plug in x for the other original problem.

y=x-4

y=(-y/3)-4

step three) solve for y.

y=(-y/3)-4

y+4=(-y/3)-4+4

3*(y+4)=(-y/3)*3

3y+12=-y

(3y+12)-3y=-y-3y

12/-4=-4y/-4

y=-3

step four) plug in -3 for y and solve for x.

y=x-4

-3=x+4

-3-4=x+4-4

-7=x

<em>I am in algebra two so you can trust my answer. if you need more help lmk in the comments. happy holidays and stay safe!</em>

5 0
2 years ago
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