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Ne4ueva [31]
2 years ago
5

3. Math test scores: 93, 86, 93, 85, 73 mean = median = mode(s) = range = © M. Tallman 2014 ww​

Mathematics
1 answer:
GalinKa [24]2 years ago
6 0

Answer:

Mean = 86

Median = 86

Mode = 93

Range = 20

Step-by-step explanation:

Mean is the average of a set of numbers. To find the average, you add all the numbers together and divide the product by how many numbers are in the set so:

93 + 86 + 93 + 85 + 73 = 430

430/5 = 86

Median is the middle of a set of numbers.

First put the numbers in order of smallest to biggest

73, 85, 86, 93, 93.

The middle number is 86 so the median is 86.

A mode or modes are numbers that appear most frequently in a number of sets. They’re can be multiple modes.

The most frequent number is 93 so the mode is 93

Range is the difference of the biggest number and the smallest number. The biggest is 93 and the smallest is 73.

93 - 73 = 20

The range is 20

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Step-by-step explanation:

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Answer:

  114 square meters

Step-by-step explanation:

The figure decomposes into two congruent trapezoids, each with bases 15 m and 4 m, and height 6 m. The area formula for a trapezoid is ...

  A = 1/2(b1 +b2)h

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Each trapezoid will have an area of ...

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The figure's area is twice that, so is ...

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6 0
3 years ago
Students in a zoology class took a final exam. They took equivalent forms of the exam at monthly intervals thereafter. After t​
juin [17]

Answer:

a. 73; b. 48.9; c. 2; d. 33.8; e. 73

Step-by-step explanation:

Assume the function was

S(t)= 73 - 15 ln(t + 1), t  ≥ 0

a. Average score at t = 0

S(0) = 73 - 15 ln(0 + 1) = 73 - 15 ln(1) = 73 - 15(0) =73 - 0 = 73

b. Average score at t = 4

S(4) = 73 - 15 ln(4 + 1) = 73 - 15 ln(5) = 73 - 15(1.61) =73 - 24.14 = 48.9

c. Average score at t =24

S(24) = 73 - 15 ln(24 + 1) = 73 - 15 ln(25) = 73 - 15(3.22) =73 - 48.28 = 24.7

d. Percent of answers retained

At t = 0. the students retained 73 % of the answers.

At t = 24, they retained 24.7 % of the answers.

\text{Percent retention} = \dfrac{\text{24.7}}{\text{73}} \times 100 \, \% = \text{33.8 \%}\\\\\text{The students retained $\large \boxed{\mathbf{33.8 \, \%}}$ of their original knowledge after two years.}

e. Maximum of the function

The maximum of the function is at t= 0.

Max = 73 %

The graph below shows your knowledge decay curve. Knowledge decays rapidly at first but slows as time goes on.

 

6 0
3 years ago
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