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Gekata [30.6K]
3 years ago
9

Find the distance from the point (-4, 4) to the line y=-2x+1 . Round your answer to the nearest tenth.

Mathematics
2 answers:
kati45 [8]3 years ago
5 0

Answer:

5 units.

Step-by-step explanation:

In order to find the distance between the line y = -2x + 1 and the point (-4, 4), we need to find the position of the line at x = -4. Shortest distance between two objects is a straight line, right?

So y = -2(-4) + 1 = 9; (-4, 9).

Finding the distance between (-4, 4) and (-4, 9) gives us the answer of 5.

almond37 [142]3 years ago
3 0

Answer:

2.2 units

Step-by-step explanation:

Equation of the Perpendicular from (-4,4) to the given line:

m1 × m2 = -1

y = (½)x + c

4 = (½)(-4) + c

c = 6

y = (½)x + 6

Foot of the Perpendicular

(½)x + 6 = -2x + 1

5/2 x = -5

x = -2

y = -2(-2) + 1 = 5

(-2,5) and (-4,4)

sqrt[(5-4)² + (-2+4)²]

sqrt(1 + 4)

sqrt(5)

2.236067977

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What is expanded form of 605,970
Luba_88 [7]
605,970 is expanded in this form:

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each number is multiplied to the corresponding place value.
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Read 2 more answers
Solve the equation. Then check your solution. – two-fifths + a = One-fifth a. Three-fifths c. StartFraction 3 Over 10 EndFractio
VLD [36.1K]

Answer:

a = Negative one-fifth

Step-by-step explanation:

The given equation is :

\dfrac{2}{5}+a=\dfrac{1}{5}

We need to find the value of a.

Subtract 2/5 from both sides.

\dfrac{2}{5}+a-\dfrac{2}{5}=\dfrac{1}{5}-\dfrac{2}{5}\\\\a=\frac{1}{5}-\frac{2}{5}\\\\a=\dfrac{-1}{5}

So, the correct answer is Negative one-fifth. Hence, the correct option is (b).

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Answer:

Problem 2): \left \{x\, |\,0\leq x\leq 240\,\,\right \}

which agrees with answer C listed.

Problem 3) :  D = (-3, 6]  and R = [-5, 7]

which agrees with answer D listed

Step-by-step explanation:

Problem 2)

The Domain is the set of real numbers in which the function (given by a graph in this case) is defined. We see from the graph that the line is defined for all x values between 0 and 240. Such set, expressed in "set builder notation" is:

\left \{x\, |\,0\leq x\leq 240\,\right \}

Problem 3)

notice that the function contains information on the end points to specify which end-point should be included and which one should not. The one on the left (for x = -3 is an open dot, indicating that it should not be included in the function's definition, therefor the Domain starts at values of x strictly larger than -3. So we use the "parenthesis" delimiter in the interval notation for this end-point. On the other hand, the end point on the right is a solid dot, indicating that it should be included in the function's definition, then we use the "square bracket notation for that end-point when writing the Domain set in interval notation:

Domain = (-3, 6]

For the Range (the set of all those y-values connected to points in the Domain) we use the interval notation form:

Range = [-5, 7]

since there minimum y-value observed for the function is at -5 , and the maximum is at 7, with a continuum in between.

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