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Rudik [331]
3 years ago
11

An outline could be best compared to _____.

Physics
1 answer:
stiv31 [10]3 years ago
5 0

Answer:

A guide

A giude teaches you everything

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What is the wavelength of a 2.50-kilohertz sound
Alexxx [7]
The formula v=fλ can be used here.

326=2500*λ

Note the 2500 as 2.5kHz is 2.5 thousand Hz.

λ = 326/2500
= 0.1304m = 0.130m
3 0
3 years ago
Which term below is known as the sum of all of the forces acting on an object?​
Sphinxa [80]
Gravity is a force acting on a object
5 0
3 years ago
Describe how the ultrasound technology or research involves electromagnetic or sound waves
motikmotik
When undergoing an ultrasound, the transducer probe of the ultrasound machine transmits sound waves. It also receives the sound waves that are reflected back after it reaches a boundary. 

The reflected waves are received by the probe and relayed to the ultrasound machine. The machine calculates the distance from the probe to the tissue or organ (boundaries) using the speed of sound in tissue and the time of the each echo's return. It then <span>displays the distances and intensities of the echoes on the display screen, forming a two dimensional image. </span>
6 0
3 years ago
Two<br>vectors Å and °B are such that A = 2<br>and A-B-C find the angle between them​
sweet-ann [11.9K]

Answer:

hjg567 A 567

Explanation:

7 0
3 years ago
Your grandfather clock's pendulum has a length of 0.9930 m.
posledela

We will start from the period definition to find the relationship between the perioricity and the length. After finding the relationship between the two lengths and periods we will proceed to calculate the length two with the loss of the period, that is

T = 2\pi \sqrt{\frac{l}{g}}

Therefore the period is proportional to the square root of the length

T \propto l^{1/2}

Then

\frac{T_2}{T_1} = \frac{\sqrt{L_2}}{\sqrt{L_1}}

(\frac{T_2}{T_1})^2 = \frac{L_2}{L_1}

L_2 = (\frac{T_2}{T_1})^2(L_1)

The period T_1 is equivalent to the seconds that a day has, that is 86400 seconds while period two will be the seconds that have one day less the loss of 16 consecutive announced in the statement therefore,

L_2 = (\frac{86400}{86384})(0.993)

L_2 = 0.99336

The total change in the lenght is

\Delta L = L_2 - L_1

\Delta L = 0.99336 - 0.993

\Delta L = 0.00036m = 3.6*10^{-4}m = 360 \mu m

Therefore the pendulum should be adjust in 360 \mu m

5 0
3 years ago
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