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Vadim26 [7]
3 years ago
5

Communicate is 25 a multiple of 2 or 5 ? how do you know?

Physics
1 answer:
PIT_PIT [208]3 years ago
6 0
It's a multiple of 5 because you can't multiply anything by 2 and get 25
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3 years ago
I need help with this physics question
insens350 [35]
It's impossible to describe WHERE a place is without mentioning ANOTHER place.

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The question is trying to get you to realize that to get from a reference point to a certain position, you have to know

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4 0
3 years ago
At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m². A fan is 30 m from the loudspeak
Klio2033 [76]

To solve this problem we will apply the concepts related to the Area, the power and the proportionality relationships between intensity and distance.

The expression for sound power is,

P = AI

Here,

A = Area

I = Intensity

P = Power

At the same time the area can be written as,

A = \frac{\pi d^2}{4}

Now the intensity is inversely proportional to the square of the distance from the source, then

I \propto \frac{1}{r^2}

The expression for the intensity at different distance is

\frac{I_1}{I_2}= \frac{r^2_2}{r_1^2}

Here,

I_1 = Intensity at distance 1

I_2 = Intensity at distance 2

r_1 = Distance 1 from light source

r_2 = Distance 2 from the light source

If we rearrange the expression to find the intensity at second position we have,

I_2 = I_1 (\frac{r_1^2}{r_2^2})

If we replace with our values at this equation we have,

I_2 = (0.10W/m^2)(\frac{1.0m^2}{30.0m^2})

I_2 = 1.11*10^{-4} W/m^2

Now using the equation to find the area we have that

A = \frac{\pi (8.4*10^{-3}m)^2}{4}

A = 5.5*10^{-5}m^2

Finally with the intensity and the area we can find the sound power, which is

P = AI

P = (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)

P = 6.1*10^{-9}J/s

Power is defined as the quantity of Energy per second, then

E = 6.1*10^{-9}J

8 0
3 years ago
A 100 V battery is connected across a
Sergio039 [100]

1 mA = 0.001 A

Therefore, 5 mA = 0.001 * 5

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Resistance = voltage / current

= 100 / 0.005

= 20000 ohms

Current = voltage / resistance

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5 0
3 years ago
Which type of drug would be useful in dilating the pupils for an examination of the retina? Which type of drug would be useful i
givi [52]

Answer:

muscarinic receptor inhibitor

Explanation:

6 0
3 years ago
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