Hello <span>an equation for the line in point-slope form and general form is : y = ax+b a : </span>slope ; the <span>Passing through (x' ; y') </span>y' = ax'+b y-y' =a(x-x') and : x' =8 y' = -4 calculate a : let : y = ax+b .....(D) ....(D') y = (1/5)x+4 .(D) perpendicular to(D') : slope (D) × slope (D') = -1
slope (D') = 1/5 slop(D)×(1/5) = -1 slope (D) = -5 equation for the line : y-y' =a(x-x') y+4 =(-5) (x-8)