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NeX [460]
4 years ago
13

Name some other action-reactions pairs that you have observed??

Chemistry
1 answer:
Phoenix [80]4 years ago
3 0

action: jimmy touched the hot stove

reaction: jimmy got burned

You might be interested in
Is it true barium ion Games to electrons to make its valence shell full
rjkz [21]

Answer:

It is false

Explanation:

Barium does not gain electrons to make its valences shell full. In truth, Barium loses electrons to attain a complete octet configuration of its shell.

This is because, barium is electropositive and not electronegative.

  • As with most metals, barium will prefer to lose two electrons when forming bonds.
  • The loss of two electrons makes it isoelectronic with the corresponding noble gas.
5 0
3 years ago
What is the name of this hydrocarbon? <br> A: propane<br> B: pentene<br> C: butene<br> D: ethane
avanturin [10]

I don't think it's any of the above. Because there is two double carbon bonds and it belongs to an alkene, it should be an ethene molecule.

3 0
3 years ago
Read 2 more answers
Which part of the water cycle creates a cooling effect for the earth?
pychu [463]
Troposphere is the answer
6 0
3 years ago
Use the mass and volume data to calculate the density of an unknown metal to the nearest hundredth.
11Alexandr11 [23.1K]

Answer:

8.90

Explanation:

Density = mass ÷ volume

D = 222.50 g ÷ 25.00

= 8.9

The density of the unknown metal is 8.90.

Hope that helps.

8 0
4 years ago
Read 2 more answers
Enter your answer in the box provided. How many grams of helium must be added to a balloon containing 6.24 g helium gas to doubl
Archy [21]

Answer : The mass of helium gas added must be 12.48 grams.

Explanation : Given,

Mass of helium (He) gas = 6.24 g

Molar mass of helium = 4 g/mole

First we have to calculate the moles of helium gas.

\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{6.24g}{4g/mole}=1.56moles

Now we have to calculate the moles of helium gas at doubled volume.

According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,

V\propto n

or,

\frac{V_1}{V_2}=\frac{n_1}{n_2}

where,

V_1 = initial volume of gas  = V

V_2 = final volume of gas = 2V

n_1 = initial moles of gas  = 1.56 mole

n_2 = final moles of gas  = ?

Now we put all the given values in this formula, we get

\frac{V}{2V}=\frac{1.56mole}{n_2}

n_2=3.12mole

Now we have to calculate the mass of helium gas at doubled volume.

\text{Mass of }He=\text{Moles of }He\times \text{Molar mass of }He

\text{Mass of }He=3.12mole\times 4g/mole=12.48g

Therefore, the mass of helium gas added must be 12.48 grams.

4 0
3 years ago
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