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nataly862011 [7]
3 years ago
13

The question is in the picture and if you don't know it please don't answer with a ridiculous response Thank you!​

Chemistry
2 answers:
Lerok [7]3 years ago
7 0

Answer: It is B.) 1s^22s^12p^1

Explanation: mind giving me brainliest? :)

Nonamiya [84]3 years ago
4 0

Answer:

ñanamaisañia ñanamaisañia

Explanation:

n

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What is the equilibrium membrane potential due to na ions if the extracellular concentration of na ions is 142 mm and the intrac
Ganezh [65]

The equilibrium membrane potential is 41.9 mV.

To calculate the membrane potential, we use the <em>Nernst Equation</em>:

<em>V</em>_Na = (<em>RT</em>)/(<em>zF</em>) ln{[Na]_o/[Na]_ i}

where

• <em>V</em>_Na = the equilibrium membrane potential due to the sodium ions

• <em>R</em> = the universal gas constant [8.314 J·K^(-1)mol^(-1)]

• <em>T</em> = the Kelvin temperature

• <em>z</em> = the charge on the ion (+1)

• <em>F </em>= the Faraday constant [96 485  C·mol^(-1) = 96 485 J·V^(-1)mol^(-1)]

• [Na]_o = the concentration of Na^(+) outside the cell

• [Na]_i = the concentration of Na^(+) inside the cell

∴ <em>V</em>_Na =

[8.314 J·K^(-1)mol^(-1) × 293.15 K]/[1 × 96 485 J·V^(-1)mol^(-1)] ln(142 mM/27 mM) = 0.025 26 V × ln5.26 = 1.66× 25.26 mV = 41.9 mV

4 0
3 years ago
Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions. If 0.212 g of KHP are dissolve
pochemuha

0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.

Potassium hydrogen phthalate, KHP, is a monoprotic acid often used to standardize NaOH solutions.

The balanced neutralization equation is:

NaOH(aq) + KHC₈H₄O₄(aq) ⇒ KNaC₈H₄O₄(aq) + H₂O(l)

  • Step 1: Calculate the reacting moles of KHP.

0.212 g of KHP react. The molar mass of KHP is 204.22 g/mol.

0.212 g × 1 mol/204.22 g = 1.04 × 10⁻³ mol

  • Step 2: Determine the reacting moles of NaOH.

The molar ratio of NaOH to KHP is 1:1.

1.04 × 10⁻³ mol KHP × 1 mol NaOH/1 mol KHP = 1.04 × 10⁻³ mol NaOH

  • Step 3: Calculate the molarity of NaOH.

1.04 × 10⁻³ moles of NaOH are in 35.00 mL of solution.

[NaOH] = 1.04 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.0297 M

0.212 g of KHP is are dissolved in 50.00 mL of water and are titrated by 35.00 mL of 0.0297 M NaOH.

Learn more about titration here: brainly.com/question/4225093

3 0
2 years ago
How many moles of carbon dioxide will be produced from the complete combustion of 13.6 moles of butane?
Aleks04 [339]

Answer:

54.4 mol

Explanation:

the equation for complete combustion of butane is

2C₄H₁₀ + 13O₂ ---> 8CO₂ + 10H₂O

molar ratio of butane to CO₂ is 2:8

this means that for every 2 mol of butane that reacts with excess oxygen, 8 mol of CO₂ is produced

when 2 mol of C₄H₁₀ reacts - 8 mol of CO₂ is produced

therefore when 13.6 mol of C₄H₁₀ reacts - 8/2 x 13.6 mol = 54.4 mol of CO₂ is produced

therefore 54.4 mol of CO₂ is produced

5 0
3 years ago
The basic structure of an amino acid contains the amine group, NH2, and a carboxylic acid group separated by one or more carbon
OLEGan [10]

The answer would be True

3 0
3 years ago
Good Morning I have a question I need help and can not find the answer o it maybe someone help me? The question is _______ Most
Semenov [28]

Answer:

hydro, water

Explanation:

3 0
3 years ago
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