Question

Find the perimeter of the polygon with the vertices X(−1, 3), Y(3, 0), and Z(−1,−2). Round your answer to the nearest hundredth

Answer 1

Answer:

The perimeter of the polygon is $P=14.47\ units$

Step-by-step explanation:

we know that

The perimeter is the sum of the length sides of the polygon

In this problem

P=XY+YZ+XZ

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance XY

we have

X(−1, 3), Y(3, 0)

substitute

$d=\sqrt{(0-3)^{2}+(3+1)^{2}}$

$d=\sqrt{25}$

$dXY=5\ units$

step 2

Find the distance YZ

we have

Y(3, 0), Z(−1,−2)

substitute

$d=\sqrt{(-2-0)^{2}+(-1-3)^{2}}$

$d=\sqrt{20}$

$dYZ=4.47\ units$

step 3

Find the distance XZ

we have

X(−1, 3), Z(−1,−2)

substitute

$d=\sqrt{(-2-3)^{2}+(-1+1)^{2}}$

$d=\sqrt{25}$

$dXZ=5\ units$

step 4

Find the perimeter

P=XY+YZ+XZ

$P=5+4.47+5=14.47\ units$