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Nonamiya [84]
3 years ago
12

a right triangle has a hypotenuse with a length of 20. the lengths of the legs are whole numbers. what are the lengths of the le

gs​
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0

Answer:

12;16

Step-by-step explanation:

The Pythagorean theorem states that

a^2+b^2=c^2 where a and b are legs of a triangle, and c is the hypotenuse.

This means that we have to find 2 values that once squared, add up to 400. (20^2)

Based on this, we can use the values of 12 and 16 to satisfy this.

12^2+16^2=144*256=400

Therefore, the legs of the triangle are 12 and 16.

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50 POINTS PLS HELP!!!
Viefleur [7K]

Answer:

1.) 90 ways

2.) 15,600 ways

3.) 24 ways

Step-by-step explanation:

1.)  Let's say   we are given 2 digits not equal to each other...The number of different orderings would be  2*1 = 2, or  if we wanted the number of ways to order 2 digits chosen :   10*9 = 90 ways

2.)   The number of ways to arrange 3 letters from 26 letters is:

26 Permutes 3  =    26! / (26 -3)!  =  26*25*24 = 15,600 ways to choose 3 letters in a certain order

3.) 4 different chores.  The number of ways to do them =  4*3*2 *1 = 24 ways

7 0
3 years ago
5y-x=10 solve for y
shusha [124]
5y-x=10\\\\ 5y=10+x \ |:5 \ Both \ sides \\\\ y=\frac{10}{5}+\frac{x}{5}\\\\ y=2+\frac{x}{5}

because
5y-x=5(2+\frac{x}{5})-x=5\cdot 2 +\frac{x}{\not5}\cdot 5 - x= 10+x-x=10



3 0
4 years ago
Add or subtract.
Karolina [17]

Answer:

is that you emme!

ok i will give a clue

6 0
3 years ago
A wire is stretched from the ground to the top of an antenna tower. The wire is 15 feet long. The height of the tower is 3 feet
Mariana [72]

The distance d is 9 ft and the height is 12ft.

<h3>How to find the distance and the height?</h3>

Here we can model the situation with a right triangle, where the length of the wire is the hypotenuse.

The height is one cathetus and the distance is the other catheti.

Let's define:

  • h = height
  • d = distance.
  • hypotenuse = 15ft

We know that the height of the tower is 3 ft larger than the distance, then:

h = d + 3ft

Now we can use the Pythagorean theorem, it says that the sum of the squares of the cathetus is equal to the square of the hypotenuse.

Then:

d^2 + (d + 3ft)^2 = (15ft)^2

Now we can solve this equation for d:

d^2 + d^2 + 6ft*d + 9ft^2 = (15ft)^2\\\\2d^2 + 6ft*d - 216 ft^2 = 0\\\\d^2 + 3ft*d - 108ft^2 = 0

Then the solutions are:

d = \frac{-3ft \pm \sqrt{(3ft)^2 - 4*(-108ft^2)} }{2} \\\\d = \frac{-3ft \pm 21ft }{2}

We only take the positive solution:

d = (-3ft + 21ft)/2 = 9ft

And the height is 3 ft more than that, so:

h = 9ft + 3ft = 12ft

The distance d is 9 ft and the height is 12ft.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

8 0
2 years ago
Is it possible to have a triangle with two right angles? Explain your reasoning.
Black_prince [1.1K]

Answer and Explanation:

Because of the fact that the sum of the three interior angles of a triangle must be 180 degrees, a triangle could not have two right angles.

6 0
4 years ago
Read 2 more answers
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