<h2><em>THERE WAS A TORNADO????????????</em></h2><h2><em></em></h2><h2><em>SAY WHAT?!</em></h2>
Answer:
distance when the weight is 8 kg is 26.66 cm
Explanation:
given data
distance d2 = 10 cm
weight w2 = 3 kg
weight w1 = 8 kg
to find out
distance when the weight is 8 kg
solution
we consider here distance d1 when weight is 8 kg
so equation will be
d1/d2 = w1/w2
d/10 = 8/ 3
so d = 8/3 × 10
so d = 26.66
distance when the weight is 8 kg is 26.66 cm
Given:
Force(F): 100 N
Acceleration: 10 m/s^2
Now we know that
F= mx a
Where F is the force acting on the object which is measured in Newton
m is the mass of the object measured in Kg
a is the acceleration measured in m/s^2
Substituting the given values in the above formula we get
100= 10m
m= 10 Kg
Answer:
The magnitude of the change in momentum of the stone is 5.51kg*m/s.
Explanation:
the final kinetic energy = 1/2(0.15)v^2
1/2(0.15)v^2 = 70%*1/2(0.15)(20)^2
v^2 = 21/0.075
v^2 = 280
v = 16.73 m.s
if u is the initial speed and v is the final speed, then:
u = 20 m/s and v = - 16.73m/s
change in momentum = m(v-u)
= 0.15(- 16.73-20)
= -5.51 kg*m.s
Therefore, The magnitude of the change in momentum of the stone is 5.51kg*m/s.
