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3 years ago

HELP PLEASE!!!!! (Apex)

2 answers:

8 0

The answer is B. Volume before + pebble’s volume= Volume after => 10ml+ pebble’s volume= 12ml => pebble’s volume= 2ml = 2cm3

Snowcat [4.5K]3 years ago

3 0

The answer is D. 12cm3

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What is the difference between organic and inorganic material?

babymother [125]

Organic materials comes from living things while inorganic materials comes from non living things

Organic materials are those composed mainly of carbon they are derived from living things while inorganic materials are derived from non living things sucjh as rocks etc

5 0

2 years ago

The speed of a rocket just after being launched is 12 m / s.

drek231 [11]

This question involves the concepts of the equations of motion, kinetic energy, and potential energy.

a. The kinetic energy of the rocket at launch is "3.6 J".

b. maximum gravitational potential energy of the rocket is "3.6 J".

<h3>a. KINETIC ENERGY AT LAUNCH</h3>

The kinetic energy of the rocket at launch is given by the following formula:

$K.E=\frac{1}{2} m v_i^2$

where,

K.E = initial kinetic energy = ?
m = mass of rocket = 0.05 kg
$v_i$ = initial speed = 12 m/s

Therefore,

$K.E=\frac{1}{2}(0.05\ kg)(12\ m/s)^2$

K.E = 3.6 J

<h3>b. MAXIMUM GRAVITATIONAL POTENTIAL ENERGY</h3>

First, we will use the third equation of motion to find the maximum height reached by rocket:

$2gh=v_f^2-v_i^2$

where,

g = -9.81 m/s²
h = maximum height = ?
vf = final speed = 0 m/s

Therefore,

2(-9.81 m/s²)h = (0 m/s)² - (12 m/s)²

h = 7.34 m

Hence, the maximum gravitational potential energy will be:

P.E = mgh

P.E = (0.05 kg)(9.81 m/s²)(7.34 m)

P.E = 3.6 J

Learn more about the equations of motion here:

brainly.com/question/5955789

4 0

2 years ago

what will be the speed of a solid sphere of mass 2.0 kilograms and radius 15.0 centimeters when it reaches the bottom of a incli

Yuki888 [10]

Explanation:

Below is an attachment containing the solution.

4 0

3 years ago

A power source of 2.0 V is attached to the ends of a capacitor. The capacitance is 4.0 μF. What is the amount of charge stored i

ioda

$C = 4 \ \mu F = 4 \cdot 10^{-6} \ F. \newline
q = Cu = 4 \cdot 10^{-6} \cdot 2 = 8 \cdot 10^{-6} = 0.000008 \ C.$

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4 years ago

Air will break down (lose its insulating quality) and sparking will result if the field strength is increased to about 3 × 106 N

CaHeK987 [17]

Answer:

Explanation:

Given

Electric Field Strength $E=3\times 10^6\ N/C$

When a charged particle enters the Electric field it Experience a force in the direction of electric field (for positive charge and vice-versa for negative charge)

charge on Electron $q=1.6\times 10^{-19}\ C$