3 years ago

Please Please Help!!, What happens when a current moves through a wire and the wire is placed near a magnet?

Physics

2 answers:

USPshnik [31]3 years ago

7 0

I think it is c not sure

LenaWriter [7]3 years ago

7 0

'd' is the correct choice. Don't make me type out the whole statement again.

You might be interested in

Which of the following does NOT describe the conversion of potential to kinetic energy?

ivann1987 [24]

I believe it would be A. (:

8 0

3 years ago

28. In the diagram above which symbol represents the light bulb ?

Tanzania [10]

28. It's B
29. It's A

3 0

4 years ago

Read 2 more answers

What two things does light provide?

labwork [276]

Answer:

Light provides brightness to see and also light carries energy

5 0

3 years ago

Which of these is an appropriate treatment for a deep, bleeding wound?

bija089 [108]

Explanation:

A. Walk the person around

4 0

3 years ago

Read 2 more answers

Two electrons in a vacuum exert force of F = 3.8E-09 N on each other. They are then moved such that they are separated by x = 8.

iren [92.7K]

Answer:

F_n = 5.65E-11 N

d = 1.20682E-31 m

Explanation:

F = 3.8E-09 N

where

m = Mass of electron = 9.109E−31 kilograms

G = Gravitational constant = 6.67E-11 m³/kgs²

x = Distance between them

$F=G\frac{m^2}{x^2}\\\Rightarrow 3.8E-09=G\frac{m^2}{x^2}$

For $F_n$

$F_n=G\frac{m^2}{x^2}\\\Rightarrow F_n=G\frac{m^2}{(8.2x)^2}\\\Rightarrow F_n=G\frac{m^2}{67.24x^2}$

Dividing the above equations we get

$\frac{F}{F_n}=\frac{G\frac{m^2}{x^2}}{G\frac{m^2}{67.24x^2}}\\\Rightarrow \frac{F}{F_n}=67.24\\\Rightarrow F_n=\frac{F}{67.24}\\\Rightarrow F_n=\frac{3.8E-09}{67.24}\\\Rightarrow F_n=5.65E-11\ N$

F_n = 5.65E-11 N

$F=G\frac{m^2}{x^2}\\\Rightarrow x=\sqrt{\frac{Gm^2}{F}}\\\Rightarrow x=\sqrt{\frac{G}{F}}m\\\Rightarrow x=\sqrt{\frac{6.67E-11}{3.8E-09}}9.109E-31\\\Rightarrow x=1.20682E-31\ m$

d = 1.20682E-31 m

8 0

4 years ago