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kakasveta [241]
2 years ago
11

A car is traveling at a speed of 37 m/s.

Physics
1 answer:
Vika [28.1K]2 years ago
3 0

1. The speed in kilometers per hour (Km/h) is 133.2 Km/h

2. Yes, the speed is exceeding the 125 Km/h limit

<h3>How to convert 37 m/s to Km/h</h3>

From the question given above, the following data were obtained:

  • Speed (in m/s) = 37 m/s
  • Speed (in Km/h) =?

We can convert 37 m/s to kilometers per hour (Km/h) by doing the following:

1 m/s = 3.6 Km/h

Therefore,

37 m/s = 37 × 3.6

37 m/s = 133.2 Km/h

Thus, 37 m/s is equivalent to 133.2 Km/h

<h3>2. How to determine if the speed is exceeding the limit</h3>
  • Speed of car = 133.2 Km/h
  • Speed limit = 125 Km/h

From the above, we can see that the speed of the car is greater than the speed limit.

Thus, we can conclude that the speed of the car is exceeding the speed limit.

Learn more about conversion:

brainly.com/question/10893215

#SPJ1

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Witch of the following is considered a renewable resource trees,oil, or coal
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Which of the following is an example of a unicellular organism?
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4 years ago
A rope attached to a sledge makes an angle of 40° with the ground. Calculate the tension in the rope required to produce a horiz
oksano4ka [1.4K]

let the tension force in the rope attached to the sledge be "T"

θ  = angle of rope with the horizontal = 40 deg

X = horizontal component of tension force "T" = 100 N

horizontal component of tension force "T" is given as

X = T Cosθ

100 = T Cos40

T = 130.54 N


Y = vertical component of the tension force = ?

vertical component of the tension force is given as

Y = T Sinθ

inserting the values

Y = (130.54) Sin40

Y = 83.91 N

7 0
3 years ago
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance x from the 50
Rom4ik [11]

Answer:

x=0.01457 m

Explanation:

From parallel axis theorem

I=Icm+mh²

where h=x

The rotational inertia about its center of mass is

Icm=mL²/12

where L=1.0 m

Thus T=4.8s  we obtain

T=2\pi \sqrt{\frac{mL^{2}/12+mx^{2}  }{mgx} }\\ T=2\pi \sqrt{\frac{L^{2} }{12gx}+x/g }\\ T^{2}=4\pi^{2}(\frac{L^{2} }{12gx}+x/g )/x\\ T^{2}x=\frac{\pi^{2} L^{2} }{3g}+(\frac{4\pi^{2} }{g})x^{2}\\   0=(\frac{4\pi^{2}  }{g} )x^{2}-(T^{2} )x+(\frac{\pi^{2}L^{2}   }{3g} )\\ 4.03x^{2}-23.04x+0.335=0

After Solving this quadratic we get

x₁=5.702 m

x₂=0.01457 m

One of the solution is an impossible value for x (x=5.70m is greater than L)

So we choose the other one

x=0.01457 m

3 0
4 years ago
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