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Oduvanchick [21]
1 year ago
5

Quadrilateral a'b'c'd' is the result of dilating quadrilateral abcd about point p by a scale factor of

Mathematics
1 answer:
Karolina [17]1 year ago
4 0

The two statements about the dilated quadrilateral a'b'c'd' are false.

bc and bc' are on the same line ( False)

The length of the cd and c'd' are the same. (False)

<h3 />

The complete question is attached with the answer below.

<h3>What is dilation?</h3>

Dilation is the process of increasing the size of an object while maintaining its shape. Depending on the scale factor, the object's size can be increased or decreased.

Here the quadrilateral abcd is dilated by the scale factor 5 / 2.So the new quadrilateral is a'b'c'd'.

The given two statements are false:-

bc and bc' are on the same line ( False)

The length of the cd and c'd' are the same. (False)

<h3 />

To know more about dilation follow

brainly.com/question/3457976

#SPJ1

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Bethany needs to solve the equation -x^2 + 4x = x - 4.
notsponge [240]

Answer:

The system of equations she could write is:

   y = -x² + 4x

   y = x - 4

The solutions are (-1 , -5) and (4 , 0)

Step-by-step explanation:

-x² + 4x = x - 4

That means two equations one quadratic which is in the left hand side and the other is linear which is in the right hand side.

They represented graphically by a parabola and a line, the solution of it will be the points of intersection of the two graphs

To find the system of equations take each side and equate it by y

∵ y = -x² + 4x

∵ y = x - 4

∴ The system of equations is:

   y = -x² + 4x

   y = x - 4

Let us solve this system using -x² + 4x = x - 4

∵ -x² + 4x = x - 4

- Subtract x from both sides

∴ -x² + 3x = -4

- Add 4 to both sides

∴ -x² + 3x + 4 = 0

- Multiply both sides by -1

∴ x² - 3x - 4 = 0

Let us use the factorization to solve it

∵ x² = (x)(x)

∵ -4 = (1)(-4)

∵ (x)(1) = x

∵ (x)(-4) = -4x

∵ x + -4x = - 3x ⇒ middle term

∴ The factors of x² - 3x - 4 are (x + 1)(x - 4)

- Substitute x² - 3x - 4 by its factors

∴ (x + 1)(x - 4) = 0

Equate each factor by 0 to find the values of x

∵ x + 1 = 0

- Subtract 1 from both sides

∴ x = -1

∵ x - 4 = 0

- Add 4 to both sides

∴ x = 4

Substitute the values of x in the equation y = x - 4 to find y

∵ y = -1 - 4

∴ y = -5

∵ y = 4 - 4

∴ y = 0

The solutions are (-1 , -5) and (4 , 0)

5 0
3 years ago
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