Answer:
Uh, the second one?
Explanation:
Try to restate the question please.
Answer:
3.54 mol
Explanation:
Step 1: Given data
- Temperature (T): 45.00 °C
Step 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 45.00°C + 273.15 = 318.15 K
Step 3: Calculate the number of moles (n) of argon gas
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 2.50 atm × 37.0 L/(0.0821 atm.L/mol.K) × 318.15 K = 3.54 mol
Molecular weight of MgSO3 = 104.3682 g/mol
181 g / 104.3682 g/mol
= 1.73 g
