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gavmur [86]
3 years ago
14

1. In general, the nucleus of a small atom is stable. Therefore, over very short distances, such as those in a small nucleus,

Chemistry
2 answers:
Dafna1 [17]3 years ago
6 0
1. In general, the nucleus of a small atom is stable. Therefore, over very short distances, such as those in a small nucleus,

a. the strong nuclear force is much greater than the electric force.


9. Uranium-238 undergoes alpha decay. Therefore, uranium-238 will


b. change into a different element altogether.

Hope these answer the questions. Have a nice day.

postnew [5]3 years ago
5 0
<h3>1. <u>Answer;</u></h3>

a. the strong nuclear force is much greater than the electric force.

<h3><u>Explanation</u>;</h3>
  • <em><u>For an atom to be stable it means it has enough amount of binding energy to hold its nucleus together permanently. </u></em>
  • Therefore, <em><u>an unstable atom lacks enough amount of binding energy to hold its nucleus permanently and thus undergoes decay to achieve stability. Unstable atoms are therefore referred to being radioactive.</u></em>
  • Small atoms are stable; <u>this is because they have equal number of protons and neutrons and thus the protons and neutrons fill up energy levels while maximizing the strong force binding the nucleus together. </u>

<h3>9.<u> Answer;</u></h3>

b. change into a different element altogether.

Uranium-238 undergoes alpha decay. Therefore, uranium-238 will  <em><u>change into a different element altogether</u></em>.

<h3><u> Explanation;</u></h3>
  • Unstable atoms undergo radioactive decay in order to achieve stability of their nucleus.
  • <em><u>Uranium-238 is an example of such atom, which may undergo decay to achieve stability.</u></em>
  • <em><u>Alpha decay is one of the types of decays,</u></em> others being beta decay and gamma decay. <em><u>In alpha decay the radioactive isotope undergoes decay such that its mass number is decreased by four and its atomic number is decreased by two.</u></em>
  • Therefore, <em><u>Uranium-238 undergoes alpha decay to form a different element whose mass number is 234 and atomic number is 90, known as thorium-234. </u></em>
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CH4 + 202 → CO2 + 2H2O<br> How many grams of O2 needed to produce 36 grams of H2O?
Kipish [7]
<h3>Answer:</h3>

64 g O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced]   CH₄ + 2O₂ → CO₂ + 2H₂O

[Given]   36 g H₂O

[Solve]   x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol O₂ → 2 mol H₂O

[PT] Molar Mass of O - 16.00 g/mol

[PT] Molar Mas of H - 1.01 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up conversion:                     \displaystyle 36 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{2 \ mol \ O_2}{2 \ mol \  H_2O})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})
  2. Divide/Multiply [Cancel Units]:                                                                       \displaystyle 63.929 \ g \ O_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

63.929 g O₂ ≈ 64 g O₂

8 0
3 years ago
Read 2 more answers
Calculate the pOH of a solution if the concentration of hydroxide ions (OH-) is 1.9 x 10-5M?
OLEGan [10]

Answer:

9.28

Explanation:

pOH refers to a measure of hydroxide ions concentration. pOH tells about the alkalinity of a solution. If pOH is less than 7 then aqueous solutions are alkaline, acidic if pOH is greater than 7 and neutral if pOH is equal to 7.

Concentration of the hydroxide ions = 1.9 x 10-5 M

pH = -log(1.9\times 10^{-5})=4.72

pOH = 14 - pH

=14 - 4.72 = 9.28

6 0
3 years ago
2 NH3 + 3 CuO →3 Cu + N₂ + 3 H₂O
Tatiana [17]

40.1g of nitrogen gas is produced.

The equation given is

2 NH₃ + 3 CuO →3 Cu + N₂ + 3 H₂O

This equation is already balanced.

When 3 moles of CuO are consumed, 1 mole of nitrogen gas is produced.

We get 1 mole of nitrogen from 3 moles of copper oxide.

We need to find the number of moles of nitrogen gas produced when 4.3 moles of copper oxide are consumed.

4.3/3 x 1 = 1.433 mols

  • 1.433 mols of nitrogen gas are produced
  • The molar mass of nitrogen gas is 14+14 = 28g
  • The amount of nitrogen gas produced in grams is 28x1.433 = 40.1g

40.1g of nitrogen gas can be made when 4.3 moles of CuO are consumed.

Learn more about molarity here:

brainly.com/question/24305514

#SPJ10

5 0
1 year ago
Think about the lab procedure you just read. Label each factor below with V for “variable” or C for “constant”.
luda_lava [24]
<h2>Answer:</h2><h3>The temperature of the gas: V</h3>

The temperature of gas is a variable quantity. It can be changed by changing energy or pressure of gas.

<h3>The amount of gas in the tube (in terms of mass and moles): C</h3>

It is a constant entity. As mass of gas once taken can not be changed by changing temperature, pressure etc.

<h3>The radius of the tube: C</h3>

The radius of tube cannot change at any rate.

<h3>The temperature of the gas (changed by the water surrounding it):  V</h3>

It can be changed by changing the temperature of water surrounding it.

<h3>The type of gas: C</h3>

It can never be changed.

<h3>The pressure of the gas: V</h3>

It can be changed by simply changing temperature and volume of gas.

8 0
3 years ago
Read 2 more answers
you have been given 250.0 mL of an aqueous solution containing 18.7grams of AgNO3. What is the molarity of solution?
Reil [10]

Hey there!:

Molar mass AgNO3 = 169.87 g/mol

Number of moles:

moles of solution = mass of solute / molar mass

moles of solution = 18.7 / 169.87

moles of solution = 0.110084 moles of AgNO3

Volume in liters:

250.0 mL / 1000 => 0.25 L

Therefore:

Molarity = moles of solution / Volume of solution ( L )

Molarity = 0.110084 / 0.25

=> 0.440 M

Hope that helps!

8 0
3 years ago
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