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ExtremeBDS [4]
3 years ago
10

Here’s another science question;( one more after this !

Chemistry
1 answer:
Lesechka [4]3 years ago
4 0

Answer:

2 CuI + K2CO3 → Cu2O + 2 KI + CO2

Explanation:

Reactants:

CuI – Copper(I) iodide source: wikipedia, accessed: 2019-09-27

Other names: Cuprous iodide source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02

Appearance: White powder | when impure: tan or brownish source: wikipedia, accessed: 2019-09-27

K2CO3 – Potassium carbonate source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02

Other names: Carbonate of potash source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02, Dipotassium carbonate source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04, Sub-carbonate of potash source: wikipedia, accessed: 2019-09-27

Appearance: White, hygroscopic solid source: wikipedia, accessed: 2019-09-27; Colourless hygroscopic crystals or hygroscopic white powder source: ICSC, accessed: 2019-09-04

Products:

Cu2O – Copper(I) oxide source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02

Other names: Cuprous oxide source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04, Dicopper oxide source: wikipedia, accessed: 2019-09-27source: ICSC, accessed: 2019-09-04, Cuprite source: wikipedia, accessed: 2019-09-27

Appearance: Brownish-red solid source: wikipedia, accessed: 2019-09-27; Yellow, red or brown crystalline powder source: ICSC, accessed: 2019-09-04

KI

Names: Potassium iodide source: wikidata, accessed: 2019-09-02, KI source: wikidata, accessed: 2019-09-02, Thyrosafe source: wikidata, accessed: 2019-09-02

CO2

Names: Carbon dioxide source: wikipedia, accessed: 2019-09-27source: wikidata, accessed: 2019-09-02source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, {{plainlist| source: wikipedia, accessed: 2019-09-27, CO2 source: wikidata, accessed: 2019-09-02

Appearance: Colorless gas source: wikipedia, accessed: 2019-09-27; Odourless colourless compressed liquefied gas source: ICSC, accessed: 2019-09-04; Colorless, odorless gas. [Note: Shipped as a liquefied compressed gas. Solid form is utilized as dry ice.] source: NIOSH NPG, accessed: 2019-09-02

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Answer:

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5 0
3 years ago
Which of the following statements about benzene is true? Multiple Choice
fenix001 [56]

Answer: option a and d

Explanation:

Option A- Benzene undergoes substitution reaction

Example : benzene reacts with chlorine to form chlorobenzene, in the presence of Iron

(iii) chloride as a catalyst

C6H6 + Cl2 ---> C6H5Cl + HCl

Option D- Benzene also undergoes addition reaction

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C6H6 + 3H2 ---> C6H12

Reasons why Option B isn't the answer

Although benzeme has degree of unsaturation but it's not five degree of unsaturation.

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If you work backwards and double the degrees of unsaturation you have 8 degrees of

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6 0
3 years ago
A closed, frictionless piston-cylinder contains a gas mixture with the following composition on a mass basis: 40% carbon dioxide
Hitman42 [59]

Answer:

W=-37.6kJ, therefore, work is done on the system.

Explanation:

Hello,

In this case, the first step is to compute the moles of each gas present in the given mixture, by using the total mixture weight the mass compositions and their molar masses:

n_{CO_2}=0.8kg*0.4*\frac{1kmolCO_2}{44kgCO_2}= 0.00727kmolCO_2\\\\n_{O_2}=0.8kg*0.25*\frac{1kmolO_2}{32kgO_2}=0.00625kmolO_2\\ \\n_{Ne}=0.8kg*0.35*\frac{1kmolNe}{20.2kgNe}=0.0139kmolNe

Next, the total moles:

n_T=0.00727kmol+0.00625kmol+0.0139kmol=0.02742kmol

After that, since the process is isobaric, we can compute the work as:

W=P(V_2-V_1)

Therefore, we need to compute both the initial and final volumes which are at 260 °C and 95 °C respectively for the same moles and pressure (isobaric closed system)

V_1=\frac{n_TRT_1}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(260+273)K}{450kPa}=0.27m^3\\ \\V_2=\frac{n_TRT_2}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(95+273)K}{450kPa}=0.19m^3

Thereby, the magnitude and direction of work turn out:

W=450kPa(0.19m^3-0.27m^3)\\\\W=-37.6kJ

Thus, we conclude that since it is negative, work is done on the system (first law of thermodynamics).

Regards.

7 0
3 years ago
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Taya2010 [7]

Answer:

These glucose molecules are stored in the liver and muscles to be used for fuel, especially during physical activity. Carbohydrates improve athletic performance by delaying fatigue and allowing an athlete to compete at higher levels for longer. nutrients, such as fat or muscle protein, are utilized to make energy.

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bagirrra123 [75]

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2 years ago
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