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maria [59]
4 years ago
15

SHOW YOUR WORK PLEASE! Jim is trying to improve his speed on the track so he can qualify for the State Championships. As he is r

unning, he goes from 70 meters/minute (beginning speed) to 106 meters/minute (final speed) in 9 seconds. What is his acceleration?
Mathematics
1 answer:
alex41 [277]4 years ago
4 0

Answer:

4 m/s²

Step-by-step explanation:

Acceleration = (106-70)/9

= 36/9

= 4ms^-2

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Samantha gathered the following information on a given day at the dog park.
Luda [366]

The number of dogs that are not puppies is 17, the number of adult dogs without long hair is 6, the number of puppy dogs with long hair is 8 and the number of puppy dogs without long hair is 7.

<h3>What is the information missing?</h3>

To complete the chart it is necessary to determine:

  • Number of dogs that are not puppies.
  • Number of puppies with and without long hair
  • Number of adult dogs without long hair

Number of dogs that are not puppies:

  • 32 (total dogs) - 15 (puppies) = 17 dogs

Adult dogs without long hair:

  • 17 (total adult dogs) - 11 (adult dogs with long hair) = 6 dogs

Puppy dogs with and without long hair

Total of puppy dogs = 15, this number can be obtained by adding 9+6 or 7+8. From these combinations, the only one that meets the rule "There are 6 more dogs that have long hair than dogs that do not have long hair" is 8 puppies with long hair and 7 puppies without long hair.

Note: This question is not written correctly; here is the correct and complete question.

Samantha gathered the following information on a given day at the dog park.

There are 32 dogs playing at the dog park.

15 of the dogs are puppies.

11 of the dogs are not puppies and have long hair.

There are 6 more dogs that have long hair than dogs that do not have long hair.

Fill in the table completely to represent Samantha’s data.

Learn more about dogs in: brainly.com/question/8565422

6 0
2 years ago
In triangle JKL, sin(b°) = three fifths and cos(b°) = four fifths. If triangle JKL is dilated by a scale factor of 2, what is ta
scoundrel [369]

Answer:

Tan(b°) = 3/4 = three fourths (C)

Step-by-step explanation:

Triangle JKL is a right angled triangle in which angle K is a right angle and angle L= b°

We would apply SOHCAHTOA from trigonometry to determine the value for each sides.

For ∆JKL

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4

From the above we know the value of each sides of ∆JKL

Find attached the diagram of the above triangle (1)

∆JKL is dilated by a scale factor = 2

Meaning we would multiply each sides of ∆JKL by 2. The values of the new triangle become:

Opposite = 2(3) = 6

Adjacent = 2(4) = 8

Hypotenuse = 2(5) = 10

To find tan(b°) of the new triangle, we would apply tangent ratio

Tan(b°) = opposite/adjacent

Tan(b°) = 6/8

Tan(b°) = 3/4

Find attached the diagram for the new triangle (2)

Diagram 3 shows the drawing of both triangles together.

From the above, we can see the angle doesn't change when a shape is dilated by a scale factor.

Therefore, tan(b°) = three fourths (C)

6 0
3 years ago
132 boys to 89 girls what's the ratio
Dafna1 [17]
132:89 is the answer
6 0
3 years ago
The sum of three consecutive odd integers is 69. find the integers
Marta_Voda [28]
Let the integers be x-2, x, x+2.

Given,

x -2 + x + x + 2 = 69

3x = 69

x = 23

Hence, the integers are 21, 23 and 25.
6 0
3 years ago
Find the volume of the composite solid. Round your answer to the nearest tenth.​
amm1812

Answer:

Volume of the Figure =825.38m^3

Step-by-step explanation:

Volume of the figure = Volume of the Upper cone+Volume of the lower cone

Volume of a cone = \pi *r^2*\frac{h}{3}

Volume of the Upper Cone with  

height=12m

radius=6m

                       3.14*6*6*\frac{12}{3}

                        =3.14*6*6*4\\\\=3.14*36*4\\\\=3.14*144\\\\=147.14m^3

Volume of the Lower cone with radius=6m and height=18m

                            =3.14*6*6*\frac{18}{3} \\\\=3.14*6*6*6\\\\=3.14*36*6\\\\=3.14*216\\\\=678.24m^3

Volume of the Whole Figure =   147.14+678.24

Volume of the Figure  =825.38m^3

4 0
3 years ago
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