Answer:
C. H 0 : μ = 7 vs. Ha : μ ≠ 7
Since the calculated value of t = -9.462 falls in the critical region t ≤-2.048
We conclude that the springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.
Step-by-step explanation:
The null hypothesis the usually the test to be performed. Here we want to check whether the water is neutral or not. Neutral water must have a pH of 7 . This can be stated as the null hypothesis. And the claim is treated as the alternate hypothesis that water in not neutral or not having pH= 7
In symbols it will be written as
H0: : μ = 7 vs. Ha : μ ≠ 7
So choice C is the best option for this hypothesis testing.
Let the significance level be 0.05
The degrees of freedom = n-1= 29-1 = 28
The critical value is t ≥ 2.048 and t ≤ - 2.048 for 0.05 two tailed test with 28 df.
The test statistic to use is t- test
t= x- u/ s/√n
The total sum is 170.9 and mean = x= 5.893
The u = 7
And the sample standard deviation is =s= 0.63
Putting the values
t= 5.893-7/0.63/√29
t= - 1.107/0.11699
t= -9.4623
Since the calculated value of t = -9.462 falls in the critical region t ≤-2.048
We conclude that the springtime water the tributary water basin around the Shavers Fork watershed is not neutral. We accept our alternate hypothesis and reject the null hypothesis.
