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VladimirAG [237]
3 years ago
12

STVU is an isosceles trapezoid. If SV = 3x - 11 and TU = x + 13, find the value of x

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
7 0
The given trapezoid will have the sides ST, TV, VU, and US. Each of these can be assigned as base or legs. By this, it can be deduced that the given sides, SV and TU are the diagonals. Because the trapezoid is isosceles, the values of SV and TU should also be equal.

                                   SV = TU
                                 3x - 11 = x + 13

Transpose the terms with x and the constants in each sides of the equation.
 
                               3x - x = 13 + 11
                                   2x = 24
                                    <em> x = 12</em>

Thus, the value of x from the equation is 12. 
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40-30=10 minutes more per day x 31 days = 310minutes in a month with 31 days.
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How can you make 0.40 into a fraction??
melamori03 [73]
<h3>2/5 is your answer. </h3><h3>▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓</h3>

☞ First, 0.40 is the same as 40/100.

But we are not done.

<u>Now, doing this you need to find the GCF (Greatest common factor) of 40, 100.</u>

2 x 2 x 5 = 20.

☞ So our GCF is 20.

Divide both the numerator and the denominator by the GCF.

40 ÷ 20 / 100 ÷ 20.

<h2>Simplify to get ☞ 2/5.</h2><h2>▬▬ι══════════════ι▬▬</h2>

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- Emacathy | Top Answerer ♫♪.ılılıll|̲̅̅●̲̅̅|̲̅̅=̲̅̅|̲̅̅●̲̅̅|llılılı.♫♪

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8 0
3 years ago
On 1st January 2020, Laurie invests P dollars in an account that pays a nominal annual interest rate of 5.5%, compounded quarter
andrezito [222]

Answer:

1) The common ratio =  1.055

2) The year in which the amount of money in Laurie's account will become double is the year 2032

Step-by-step explanation:

1) The given information are;

The date Laurie made the investment = 1st, January, 2020

The annual interest rate of the investment = 5.5%

Type of interest rate = Compound interest

Therefore, we have;

The value, amount, of the investment after a given number of year, given as follows;

Amount in her account = a, a × (1 + i), a × (1 + i)², a × (1 + i)³, a × (1 + i)ⁿ

Which is in the form of the sum of a geometric progression, Sₙ given as follows;

Sₙ = a + a × r + a × r² + a × r³ + ... + a × rⁿ

Where;

n = The number of years

Therefore, the common ratio = 1 + i = r = 1 + 0.055 = 1.055

The common ratio =  1.055

2) When the money doubles, we have;

2·a = a × rⁿ = a × 1.055ⁿ

2·a = a × 1.055ⁿ

2·a/a = 2 = 1.055ⁿ

2 = 1.055ⁿ

Taking log of both sides gives;

㏒2 = ㏒(1.055ⁿ) = n × ㏒(1.055)

㏒2 = n × ㏒(1.055)

n = ㏒2/(㏒(1.055)) ≈ 12.95

The number of years it will take for the amount of money in Laurie's account to double = n = 12.95 years

Therefore, the year in which the amount of money in Laurie's account will become double = 2020 + 12..95 = 2032.95 which is the year 2032

The year in which the amount of money in Laurie's account will become double = year 2032.

3 0
3 years ago
-4x+y=23 and 4x-9y=-15
astra-53 [7]

Answer:  x= -6; y= -1

Step-by-step explanation:

-4x + y = 23

4x - 9y = - 15

-4x + y = 23

      y = 23 + 4x     [Add 4x to both side]

4x - 9(23 + 4x) = - 15

4x - 207 - 36x = - 15

-32x - 207 = -15

-32x = 192             [Add 207 to both side]

    x = -6                [Divide -32 from both side]

-4x + y = 23

-4(-6) + y = 23          [Plug in -6 for x]

24 + y = 23              [Subtract 24 from both side]

       y = -1

5 0
3 years ago
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