Answer:
A. 9x^4 and 3x^5y
Step-by-step explanation:
there are two ways to solve this:
first way:
You can solve this my substituting numbers for x and y in this case i used 2 for x and 3 for y and see which one is equal to the original equations
the second way is the regular way
when you add or subtract numbers with variables and exponents you want to add the constants and add the exponents in this case 
is the same as 
= 
and you can do the same process for subtraction
= 
9514 1404 393
Answer:
x ≠ 3
Step-by-step explanation:
In any case, the domain is restricted to values of the variable for which the function is defined. The value 1/0 is not defined, so the variable cannot allow the denominator to be zero. The denominator x-3 will be zero for x=3, so that value of the variable cannot be in the domain.
The domain is all real numbers except x=3.
_____
<em>Additional comments</em>
It is useful to become familiar with the domains of different functions. As we saw above, the reciprocal of 0 is undefined. The square root of a negative number is undefined. The log of a non-positive number is undefined. Trig functions are defined everywhere, but their inverse functions are not. Polynomial functions are defined everywhere, but ratios of polynomials have the same restriction on denominators that we see above.
Answer:
I actual foot represents 0.01093 foot on paper
Step-by-step explanation:
Given that :
Actual side length of snack stand = 60 feets
Length of side on map = 20cm
Scaie :
60 feet = 20cm
1 foot = (20/60) cm
1 foot = 0.333 cm
1cm = 0.0328084 foot
0.333cm = (0.33 * 0.0328084) = 0.01093 feets
Scale :
I actual foot represents 0.01093 foot on paper
Answer:
46%
Step-by-step explanation:
<u>Step 1: Make an expression</u>
<u />
<u>Step 2: Divide both sides by 39</u>
<u />
<u>Step 3: Find the percent</u>
<u />
-> Gives us the increased percent
46%
Answer: 46%
"He starts both trains at the same time. Train A returns to its starting point every 12 seconds and Train B returns to its starting point every 9 seconds". Basically, what you need to do is find the least common multiple. The least common multiple of 12 and 9 is 36, so the least amount of time, in seconds, that both trains will arrive at the starting points at the same time is 36 seconds.
